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igomit [66]
3 years ago
5

The bar graph shows a company's income and expenses over the last 5 years

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

The Answer:D

Step-by-step explanation:

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Find the area of the pentagon
Korvikt [17]

Answer:

A=1

45(5+25)a2

Step-by-step explanation:

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3 years ago
X^2-3×=2 use quadratic equation ​
abruzzese [7]

Answer:

(-3+√17 )/2. or( -3-√17)/2

hope you got it

4 0
3 years ago
-5t+3= -4<br> please answer this question<br> and show your work also
astraxan [27]

Answer:

t=7/5

Step-by-step explanation:

If you subtract 3 from each side, you end up with -5t=-7. In order to keep t isolated, you would have to divide -5 on both sides. When you do this, you will end up with t= -7/-5. You also need to simplify that. When simplified you end up with t=7/5. Hope this helps!

6 0
2 years ago
Read 2 more answers
Quiz
alisha [4.7K]

Answer:

the first one

Step-by-step explanation:

(-5+5) will equal 0. Because of the zero property no matter what you multiply it by it will equal 0. Same thing with (9-9)

7 0
3 years ago
Find five consecutive integers such that: "the sum of the first and 4 times the third is equal to 60 less than 3 times the sum o
Monica [59]

Consecutive integers are integers that come one after another in order. For example, 2, 3, and 4 are all consecutive integers, as well as 100, 101, and 102. In general, if we have some integer n, the consecutive integers following it will be n + 1, n + 2, n + 3, etc. Here, we have five. If we

  • Call the first integer n,
  • Then the second integer will be n + 1,
  • The third will be n + 2,
  • The fourth will be n + 3,
  • And the fifth will be n + 4.

Now, let's break down the equation in English. We'll use #1, #2, #3, #4, and #5 as stand-ins for the five integers just so we can get things set up, then we'll replace them with the expressions we came up with in the first part. Starting from the beginning of the statement, let's translate words to symbols:

  • "The sum of the first and 4 times the third" → #1 + 4 × #3
  • "is equal to" → = (maybe obvious, but still!)
  • "60 less than 3 times the sum of the second, fourth, and fifth" → 3 × (#2 + #4 + #5) - 60

Putting that all together, we get the equation

#1 + 4 × #3 = 3 × (#2 + #4 + #5) - 60.

Replacing our stand-ins for the expressions we came up with, it becomes

n + 4(n + 2) = 3[(n + 1) + (n + 3) + (n + 4)] - 60

We can now start to simplify our equation to find n (the first integer) and the rest will follow easily from that. I'll start by focusing on the left side. We can distribute and combine like terms like so:

n + 4(n+2) = n + 4n + 8 = 5n + 8

Dealing with the right, we can get rid of some redundant parentheses and carry out the same process:

3[(n + 1) + (n + 3) + (n + 4)] - 60 = 3(n + 1 + n + 3 + n + 4) - 60

= 3(3n + 8) - 60 = 9n + 24 - 60 = 9n - 36

Our simplified equation now becomes

5n + 8 = 9n - 36.

Subtracting 5n from either side:

8 = 4n - 36

Adding 36 to either side:

44 = 4n

And dividing either side by 4:

11 = n.

We now know that our first integer is 11, which means that our 5 consecutive integers are 11, 12, 13, 14, and 15.

7 0
3 years ago
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