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4 years ago

How do you estimate large numbers?

1 answer:

4 0

The best way to estimate large numbers is to find out how many units is in the number. For example, when you are dealing with millions you need to estimate the number of items closest to the large number. Ex. 1, 899,000 estimating this number is basically saying close to 2 million because the number to the right is higher then 5 so the number goes up.

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Karen set her watch 1 second behind, and it falls behind another 2 seconds every day. How many days has it been since Karen last

Kay [80]

Answer:

The equation to find the answer is $9=1+(n-1)2$ .

It has been 5 days since Karen has set her watch.

Step-by-step explanation:

Given:

Karen set her watch 1 second behind

So we will consider;

First term 'a' = 1 second

Also Given :

it falls behind another 2 seconds every day.

So we can consider;

Common difference = 2

We need to find number of days it has been 9 seconds since Karen last set her watch

Solution:

Let number of days be represented by 'n'.

Also Let $T(n) = 9$

Now By Applying formula for Arithmetic Progression we get;

$T(n)=a+(n-1)d$

Substituting the given values we get;

$9=1+(n-1)2$

Hence The equation to find the answer is $9=1+(n-1)2$ .

On Solving the above equation we get;

Subtracting both side by 1 we get;

$9-1=1+(n-1)2-1\\\\8=(n-1)2$

Now Dividing both side by 2 we get;

$\frac{8}{2}=\frac{(n-1)2}{2}\\\\4=n-1$

Adding 1 on both side we get;

$4+1=n-1+1\\\\n=5$

Hence It has been 5 days since Karen has set her watch.

3 0

4 years ago

Intercept from a table

gladu [14]

$\bf \begin{array}{ccll} x&y\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \boxed{14}&\boxed{-5}\\ 21&-3\\ \boxed{28}&\boxed{-1} \end{array}\impliedby \textit{we'll use two points to get the slope}$

$\bf (\stackrel{x_1}{14}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{28}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{28-14}\implies \cfrac{-1+5}{28-14} \\\\\\ \cfrac{4}{14}\implies \cfrac{2}{7} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{2}{7}(x-14) \\\\\\ y+5=\cfrac{2}{7}x-4$

now, to get the y-intercept, we simply set x = 0 and solve for y, and to get the x-intercept, we set y = 0 and solve for x.

$\bf \stackrel{\textit{y-intercept, x = 0}}{y+5=\cfrac{2}{7}(0)-4}\implies y+5=-4\implies y=-9\qquad \qquad \stackrel{y-intercept}{(0~,-9)}\\\\ -------------------------------\\\\ \stackrel{\textit{x-intercept, y = 0}}{(0)+5=\cfrac{2}{7}x-4}\implies 5=\cfrac{2x}{7}-4\implies 9=\cfrac{2x}{7}\implies 63=2x \\\\\\ \cfrac{63}{2}=x\implies 31\frac{1}{2}=x\qquad \qquad \qquad \qquad \qquad \qquad \qquad \stackrel{x-intercept}{\left( 31\frac{1}{2}~,~0 \right)}$

8 0

3 years ago

Simplify: (4b + 3) (2b - 5).

igomit [66]

(4b+3) (2b−5)

(4b+3) (2b+−5)

(4b) (2b) + (4b) (−5) +(3) (2b) +(3) (−5)

8b²−20b+6b−15.

= 8b²−14b−15.

5 0

4 years ago

10x•5y•10=30 find the x and y intercept

GalinKa [24]

Y=mx + b
10x.5y.10=30
10x.5y=30-10
10x.5y=20
5y= -10x + 20
5/5 = -10/5(x) + 20/5
Y= -2x +4

3 0

4 years ago

Find the area of the shape shown below

RSB [31]

Answer:

12 units squared

Step-by-step explanation:

You need to find the area of each individual shape, and then add them together. The area of the square is 4 units squared. The triangle on the left is two units squared (base times height, divided by two,) and the area of the triangle on the left is 6. Add them all together, and you get 12 units squared.

5 0

3 years ago

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