Distance = 100 m = 100/1000 = 0.1 km speed of train = 50 km/hr speed of horse = 56 km/hr resultant speed = (56 – 50) 6 km/hr time = distance/speed time = 0.1/6 = 1/60 hr = 1 min
So just use a calculator but here goes
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729
and 3^7 is 2187 which is excluded
The equation of the rotating light is an illustration of a secant function
The equation that represents the distance between the center of the circle and the light source is 
<h3>How to determine the equation</h3>
The equation is a secant function represented by
Where:
A represents the amplitude
So, we have:
--- the distance of the light from each square wall
B represents the period, and it is calculated as:
The light completes its full rotation every 6 seconds.
This means that,
T = 6
So, we have:
Simplify
Substitute values for A and B in
Rewrite as a function
Hence, the equation that represents the distance between the center of the circle and the light source is
Read more about trigonometry functions at:
brainly.com/question/1143565
Answer:
A rational number is a number that can be made by dividing two integers (an integer is a number with no fractional part). The word rational includes the word "ratio." Rational numbers are basically numbers, either positive or negative that you get by dividing 2 numbers. Any number is a rational number, even fractions and decimals, except pi due to the fact that it's a irrational number.
Step-by-step explanation:
Examples of rational numbers include, 1, which you get by dividing 1 by 1, 2 which you get by dividing 2 by 1 and 2.12, which you get by dividing 212 by 100.
Answer:
2
Step-by-step explanation:
There are two lines of symmetry and here I list them:
1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).
2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.
A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.
So, we only have 2 symmetry lines.
