I hope this helps you
x=5+y
5 (5+y)+2y= 4
25+5y+2y=4
7y= -21
y= -3
x=5+y
x=5-3 x= 2
Answer:
14 boys paid for the full year fee and 4 boys paid for the partial year fee
Step-by-step explanation:
Create a system of equations, where x is the number that paid for the $24 fee and y is the number that paid for the $16 fee:
24x + 16y = 400
x = y + 10
Solve by substitution by plugging in y + 10 as x:
24x + 16y = 400
24(y + 10) + 16y = 400
Solve for y:
24y + 240 + 16y = 400
40y + 240 = 400
40y = 160
y = 4
Then, plug in 4 as y to find x:
x = y + 10
x = 4 + 10
x = 14
So, 14 boys paid for the full year fee and 4 boys paid for the partial year fee.
1. C
2. 3, because I used a proportion table
Answer:
so the answer is B,D,E,F
and question a is B i guess
Things we know:
Six total pots = # of 10" + # of 8"
$78 total = cost of 10" + cost of 8"
So:
6 = x +y
and
78 = x*(cost of x) + y * (cost of y)
78 = x*12 + y*15
We need:
x+y=6 AND 12x+15y=78
So our answer can only be B.
