The answer to this question would be the second option “10m + 5 > 100” because 10 a month so (10m) then he purchases 5 extra per month so + 5 then his total collection is MORE so greater than 100 games so > 100 so the outcome is “10m + 5 > 100”
Answer:
t = -2
Step-by-step explanation:
5t - 26 = 18t
Add 26 to both sides:
5t - 26 + 26 = 18t + 26
Simplify:
5t = 18t + 26
Subtract 18t from both sides:
5t - 18t = 18t + 26 - 18t
Simplify:
-13t = 26
Divide both sides by -13:
-13t/-13 = 26/-13
Therefore:
t = -2
I hope this helps!
Answer:
Step-by-step explanation:
1. 2x - 9y = 23
2 x = 9 y + 23
y = (2 x)/9 - 23/9
2 x - 9 y - 23 = 0
2. 5x - 3y = -1
5 x + 1 = 3 y
y = (5 x)/3 + 1/3
5 x - 3 y + 1 = 0
I belive that should help you out a bit :D
If the limit of f(x) as x approaches 8 is 3, can you conclude anything about f(8)? The answer is No. We cannot. See the explanation below.
<h3>What is the justification for the above position?</h3>
Again, 'No,' is the response to this question. The justification for this is that the value of a function does not depend on the function's limit at a given moment.
This is particularly clear when we consider a question with a gap. A rational function with a hole is an excellent example that will help you answer this question.
The limit of a function at a position where there is a hole in the function will exist, but the value of the function will not.
<h3>What is limit in Math?</h3>
A limit is the result that a function (or sequence) approaches when the input (or index) near some value in mathematics.
Limits are used to set continuity, derivatives, and integrals in calculus and mathematical analysis.
Learn more about limits:
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1) -3(5x+2y=-3)⇒ -15x-6y=9
⇒ -9x=27
2(3x+3y=9)⇒ 6x+6y=18
2) -9x/-9=27/-9 ⇒ x=-3
3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6
Answer: (-3,6)
Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.
Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em>
