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Alona [7]
2 years ago
11

Solve the logarithmic equation. Round to the nearest ten-thousandth if necessary. log(x+9)-log x=3

Mathematics
1 answer:
zheka24 [161]2 years ago
4 0
(√6,0) (√5,-1) (-√6,0) (-√5,-1)
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Joel wanted his mom to buy a super-sized box of his favorite cereal, but his mom didn't think it would fit in her cupboard. The
Lorico [155]
<h3><u>Given</u>:-</h3>

  • Volume 6,900 cm^3
  • Length = 23 cm
  • Width = 10cm

<h3><u>To Find</u>:-</h3>

  • Height of box ??

<h3><u>Solution</u>:-</h3>

\\\diamond{\underline{\underline{\sf {\;\; Calculating\; Height\;  of  \; box :-}}}}\\

\\ \pink \star \:  \: {\underline{\boxed {\bf{  Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h }}} }\; \red\bigstar  \\

Where,

  • » l denotes Length
  • » w denotes Width
  • » h denotes Height

\\  \sf \implies \: {Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \: 23 \:    \times  \: 10 \:   \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \:  230 \:   \times \:   h} \\

\\  \sf \implies \: {  \: h  \:   = \:   \frac{6900}{230}  \:  } \\

\\  \sf \implies \: {  \: h  \:   = \:   30 \: {cm }^{3}   \:   } \\

\\ \implies{\underline{\boxed{\frak { Height = 30  \: cm^3 }}}} \; \purple\bigstar \:  \\

\\\qquad \rule{120pt}{3pt}\\

Therefore , the Volume of the Box is 30 cm ³.

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The interior angles of a pentagon all add up to be 540°
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