a. Jada got the measurement 16m.
b. The measured depth differ 0.2m from the actual depth.
c. There is a 12.66% error in calculation.
Step-by-step explanation:
Given,
The depth of lake = 15.8 m
a. Jada accurately measured the depth of the lake to the nearest meter. What measurement did Jada get
When a digit after the decimal point is 5 or more than that, the number before decimal is rounded to the next number.
Therefore,
15.8 rounded to nearest number is 16.
The depth of lake measured by Jada = 16 m
Jada got the measurement 16m.
b. By how many meters does the measured depth differ from the actual depth?
Difference = Approx - Exact
Difference = 16 - 15.8 = 0.2m
The measured depth differ 0.2m from the actual depth.
c. Express the measurement error ad a percentage of the actual depth.
Percent error = 
Percent error = 
Percent error = 12.66%
There is a 12.66% error in calculation.
Keywords: percent, error
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Answer:
0
Step-by-step explanation:
5a-3=5a-3
or, 5a-5a=-3+3
or, 0=0 answer
Answer:
i think its c
Step-by-step explanation:
Hope this helps!!
Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
60x - 12 = 14x^2 + 14x
Subtract 60x & Combine
-12 = 14x^2+14x-60x
-12= 14x^2-46x
Add 12
0= 14x^2-46x-14