3 years ago

What is the equation of the line that contains (4,-1) and is perpendicular to y=5x+4

Mathematics

1 answer:

stellarik [79]3 years ago

4 0

Answer:

y/4-4/5

Step-by-step explanation:

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allochka39001 [22]

Answer:

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Step-by-step explanation:

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2 years ago

Help pleaseee! with geometry

8_murik_8 [283]

Answer:

2x(x+6)(x-6)

Step-by-step explanation:

2x³-72

2x(x²-36)

2x(x+6)(x-6)

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3 years ago

X² - x - 6 = 0 Solutions?

Ira Lisetskai [31]

Factors of -6 that add up to -1:

(x - 3)(x + 2)

Set them to 0 and solve for x

x = 3 

x = -2

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3 years ago

What value is equivalent to 32 · 43?

Yuri [45]

Answer:

1376

Step-by-step explanation:

32 · 43 = 32 x 43

=> 32 x 43 = 1376.

Therefore, 1376 is our answer.

Hoped this helped.

5 0

3 years ago

Read 2 more answers

Line segments JK and JL in the xy-coordinate plane both have a common endpoint J(-4,11) and midpoints at M, (2, 16) and M2 (-3,5

ohaa [14]

Answer:

12.1

Step-by-step explanation:

We use the formula for the distance between two arbitrary points $(x_1,y_1)$ and $(x_2,y_2)$ in the xy-coordinate plane, that is:

$d=\sqrt{(x_1-x_2)^2 + (y_1-y_2)^2}$

So, replacing the points $M=(2,16)$ and $M_2=(-3,5)$ , we obtain:

$d=\sqrt{(2-(-3))^2 + (16-5)^2}\\d=\sqrt{(2+3)^2 + (16-5)^2}\\d=\sqrt{5^2 + 11^2}\\d=\sqrt{146 }=12.083045... \simeq 12.1$

that is the answer.

note: observe that we only use the coordinates between the two midpoints and not the point J.

5 0

3 years ago