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lidiya [134]
4 years ago
15

Which of these numbers is the smallest A .0134, B .802, C .47, D.0562, E .137

Mathematics
2 answers:
kumpel [21]4 years ago
8 0

Okay sugar plum here is the answer and why it is.

The answer is D.

The bigger the number behind the decimal, the smaller it is.

Georgia [21]4 years ago
3 0
I think your answer would be D.0562
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What is the solution to the inequality below x2>25​
4vir4ik [10]

Answer:

Ans: (-5, 5)

-5 < x < 5

Step-by-step explanation:

Standard form: f(x) = x^2 - 25 < 0.

First solve x^2 - 25 = 0 --> x = +- 5

Use the algebraic method to solve f(x) < 0. Between the 2 real roots (-5) and (5), f(x) < 0, as opposite in sign to a = 1.

Answer by open interval: (-5, 5)

3 0
3 years ago
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Find the ratio and unit rate.<br> 216 cherry pieces in 6 bags of candy
Charra [1.4K]

Answer:

216:6 ratio

36 rate

Step-by-step explanation:

3 0
3 years ago
HELPPPPPPPPPPPPPPPP
Kitty [74]

Answer:

He can make 3 batches of soup.

Step-by-step explanation:

Starting with 10 pounds of tomatoes and taking out the number of pounds he sets aside for spaghetti sauce, 2.8, we have:

10-2.8 = 7.2 pounds left.

0.2 is read as "two tenths," so 7.2 = 7 2/10

We divide this remaining number of pounds by 2 2/5 for each batch of soup:

7 2/10 ÷ 2 2/5

Convert each to an improper fraction:

72/10 ÷ 12/5

Multiply by the reciprocal:

72/10 × 5/12 = 360/120 = 3

7 0
3 years ago
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What is 1 2/3 equal to
atroni [7]

Answer:

1 2/3 = 5/3

6 3/4 = 27/4

-9 7/3 = -34/3

4 2/7 = 30/7

Step-by-step explanation:

7 0
3 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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