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3 years ago

Which best describes the relationship between the two triangles below?

Mathematics

1 answer:

Nostrana [21]3 years ago

3 0

Answer:

They are SIMILAR triangles

Step-by-step explanation:

Given triangles MNL and FHG with two of their angles to be 51° and 36° respectively. Their third angle is expressed as:

180°-(51°+36°)

= 180°-87°

= 93°

Their third angle is 93°

Since both triangles have the same angles in them, both triangles are considered as similar triangle even though the value of their sides are different due to angle differences in both.

Note that individual triangles are scalene triangles since their angles are not the same but the both triangles are similar triangles based on their relationship.

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Can you help me solve for x on this equation 2x+8=3x-4

Paul [167]

Answer: 12

Step-by-step explanation:

2x + 8 = 3x - 4

In order to solve for x, we must isolate x. We can do this by moving all of the numbers with "x" in it to the left side of the equal side, and move everything else to the right of it!

Let's start off by subtracting 8 from both sides. Remember : what you do to one side, you must do it to the other.

2x + 8 - 8 = 3x - 4 - 8

Simplify!

2x = 3x - 12

Now, let's subtract 3x from both sides.

2x - 3x = 3x - 12 - 3x

Simplify!

-x = -12

Divide both sides by -1.

-x ÷ -1 = -12 ÷ -1

Simplify.

x = 12

4 0

3 years ago

Read 2 more answers

A store charges 6% VAT on all sales.<br>What is the total cost of a shirt marked at $30

AURORKA [14]

Answer:

$31.8

Step-by-step explanation:

Assuming the 6% tax is separate from the $30, we can use this equation:

Total = Cost + Tax (pretty self explanatory)

Method 1

Total = $30 + (6% * $30)

Total = $30 + $1.8

Total = $31.8

Method 2

Total = $30 * 1.06 (The 1 is the original cost, the .06 is the 6% tax)

Total = $31.8

8 0

3 years ago

A costumer placed an order with a bakery for muffins.The Baker has completed 37.5% of the order after baking 81 muffins. How man

Elza [17]

216 ? Maybe . I think you have to multiply 81 times .375 you move the decimal two places over . I believe that’s how you do the problem

5 0

3 years ago

Read 2 more answers

Write the number in scientific notation. 322,000,000

Crazy boy [7]

It would be 3.22x10^8
have a good day

8 0

3 years ago

Read 2 more answers

Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases: a. Central area 5 .

Flauer [41]

Answer:

a) "=T.INV(0.025,10)" and "=T.INV(1-0.025,10)"

And we got $t_{\alpha/2}=-2.228 , t_{1-\alpha/2}=2.228$

b) "=T.INV(0.025,20)" and "=T.INV(1-0.025,20)"

And we got $t_{\alpha/2}=-2.086 , t_{1-\alpha/2}=2.086$

c) "=T.INV(0.005,20)" and "=T.INV(1-0.005,20)"

And we got $t_{\alpha/2}=-2.845 , t_{1-\alpha/2}=2.845$

d) "=T.INV(0.005,50)" and "=T.INV(1-0.005,50)"

And we got $t_{\alpha/2}=-2.678 , t_{1-\alpha/2}=2.678$

e) "=T.INV(1-0.01,25)"

And we got $t_{\alpha}= 2.485$

f) "=T.INV(0.025,5)"

And we got $t_{\alpha}= -2.571$

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

We will use excel in order to find the critical values for this case

Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases:

a. Central area =.95, df = 10

For this case we want 0.95 of the are in the middle so then we have 1-0.95 = 0.05 of the area on the tails. And on each tail we will have $\alpha/2=0.025$ .

We can use the following excel codes:

"=T.INV(0.025,10)" and "=T.INV(1-0.025,10)"

And we got $t_{\alpha/2}=-2.228 , t_{1-\alpha/2}=2.228$

b. Central area =.95, df = 20

For this case we want 0.95 of the are in the middle so then we have 1-0.95 = 0.05 of the area on the tails. And on each tail we will have $\alpha/2=0.025$ .

We can use the following excel codes:

"=T.INV(0.025,20)" and "=T.INV(1-0.025,20)"

And we got $t_{\alpha/2}=-2.086 , t_{1-\alpha/2}=2.086$

c. Central area =.99, df = 20

For this case we want 0.99 of the are in the middle so then we have 1-0.99 = 0.01 of the area on the tails. And on each tail we will have $\alpha/2=0.005$ .

We can use the following excel codes:

"=T.INV(0.005,20)" and "=T.INV(1-0.005,20)"

And we got $t_{\alpha/2}=-2.845 , t_{1-\alpha/2}=2.845$

d. Central area =.99, df = 50

For this case we want 0.99 of the are in the middle so then we have 1-0.99 = 0.01 of the area on the tails. And on each tail we will have $\alpha/2=0.005$ .

We can use the following excel codes:

"=T.INV(0.005,50)" and "=T.INV(1-0.005,50)"

And we got $t_{\alpha/2}=-2.678 , t_{1-\alpha/2}=2.678$

e. Upper-tail area =.01, df = 25

For this case we need on the right tail 0.01 of the area and on the left tail we will have 1-0.01 = 0.99 , that means $\alpha =0.01$

We can use the following excel code:

"=T.INV(1-0.01,25)"

And we got $t_{\alpha}= 2.485$

f. Lower-tail area =.025, df = 5

For this case we need on the left tail 0.025 of the area and on the right tail we will have 1-0.025 = 0.975 , that means $\alpha =0.025$

We can use the following excel code:

"=T.INV(0.025,5)"

And we got $t_{\alpha}= -2.571$

8 0

3 years ago