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goblinko [34]
3 years ago
11

I WILL MARK BRAINLIEST!

Mathematics
2 answers:
rusak2 [61]3 years ago
7 0
Hey looks like u need help I'll help you,


So you'll need your cal for this. But I'll help anyway


A= x(4x-2) then distribute the x to get A=4x²-2x

Then plug in the 8 and get A=4(8)²-2(8)
A=256-16
A=240
Answer is 240


ipn [44]3 years ago
3 0
The answer is 4x2-5x;Area= 114 in<span>2 i think</span>
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A) scrieti toate numerele naturale impare mai mici decat 17
AURORKA [14]

1, 3, 5, 7, 8, 11, 13, 15  is the answer.

5 0
3 years ago
The table shows the total number of pictures Cal took by the end of each week.
CaHeK987 [17]

Answer:

45 pictures

Step-by-step explanation:

I did this one too but i don't if they changed the answer good luck I would double check

6 0
3 years ago
Read 2 more answers
i have 17 coins. N of them are nickels and the rest are dimes. write an expression in two different ways for the amount of money
sergiy2304 [10]

Answer:

0.05N - 0.1N + 1.7 (in dollars

1.7 - 0.05N (in dollars)

Step-by-step explanation:

Given :

Total number of coins = 17

Number of nickels = N

Number of dimes = 17 - N

1 nickel = 5 cent = $0.05

1 dime = 10 cent = $0.1

The amount of money :

(Value of nickel * number of nickels) + (value of dime * number of dime)

(0.05 * N) + (0.1 * (17-N))

0.05N + 1.7 - 0.1N

0.05N - 0.1N + 1.7

-0.05N + 1.7 = 1.7 - 0.05N

4 0
3 years ago
HELP ASAP!!! Which equation can be used to find the answer?  Jorge is selling raffle tickets for the carnival. He has sold 47 ti
loris [4]
Just do 47+118 and it equals 165. Jorge started with 165 tickets.
3 0
3 years ago
Read 2 more answers
Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
erica [24]
At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1 - r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &1013\\&#10;I=\textit{initial amount}\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &0\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1- r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &1013\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &t\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


7 0
3 years ago
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