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Leya [2.2K]
3 years ago
7

Evaluate the equation 9!/3!

Mathematics
2 answers:
Sonja [21]3 years ago
6 0

Answer:

Step-by-step explanation:

i think all you have to do for evaluating 9/3 is dividing 9 and 3.. which then would equal 3

so the answer would be 3

larisa [96]3 years ago
5 0

Answer:

60480

Step-by-step explanation:

This is an expression, not an equation (there's no = symbol here).

            9!       9·8·7·6·5·4·3!

9!/3! = ------ = ----------------------   We can cancel the 3!, resulting in:

             3!                 3!

9·8·7·6·5·4

If desired, this can be multiplied out, resulting in

72·42·20 = 3024·20 = 60480

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WILL MARK BRAINLYEST.
gtnhenbr [62]

Answer:

1) The straight line on the graph below intercepts the two coordinate axes. The point where the line crosses the x-axis is called the [x-intercept]. The [y-intercept] is the point where the line crosses the y-axis. Notice that the y-intercept occurs where x = 0, and the x-intercept occurs where y = 0.

2) There's another important value associated with graphing a line on the coordinate plane. It's called the "y intercept" and it's the y value of the point where the line intersects the y- axis. For this line, the y-intercept is "negative 1." ... This point will always have an x coordinate of zero.

Step-by-step explanation:


8 0
3 years ago
What is the ordered pair or real numbers for which x + y = 99 and x^2 - y^2 = 99.
skad [1K]

Given : x + y = 99 ------------ [1]

Given : x² - y² = 99

We know that : (x² - y²) = (x + y)(x - y)

⇒ (x + y)(x - y) = 99

⇒ 99(x - y) = 99

⇒ x - y = 1 ------------- [2]

Adding Equation [1] and [2], we get :

⇒ (x + y) + (x - y) = 99 + 1

⇒ 2x = 100

⇒ x = 50

Substituting x = 50 in Equation [1], we get :

⇒ 50 + y = 99

⇒ y = 99 - 50

⇒ y = 49

So, The Ordered pair (x , y) = (50 , 49)

5 0
3 years ago
Divide squared 9x^2 by squared 18y^2
MAVERICK [17]
Answer(C)

√(9x^2)= 3x
√(18y^2)=3y/√2= 3y/√2 X √2/√2
=3√2y/2
3 0
3 years ago
Read 2 more answers
The price of a car was decreased by 20% to £720. What was the price before the decrease?
Gemiola [76]

Answer:

say x is the original price so

x - (20x/100) = 720

720 is the balance we got after deducting the original price,

therefore; 720 = (80x/100)

You can simply solve for x now.

answer:

x = 900

4 0
3 years ago
find a curve that passes through the point (1,-2 ) and has an arc length on the interval 2 6 given by 1 144 x^-6
taurus [48]

Answer:

f(x) = \frac{6}{x^2} -8 or f(x) = -\frac{6}{x^2} + 4

Step-by-step explanation:

Given

(x,y) = (1,-2) --- Point

\int\limits^6_2 {(1 + 144x^{-6})} \, dx

The arc length of a function on interval [a,b]:  \int\limits^b_a {(1 + f'(x^2))} \, dx

By comparison:

f'(x)^2 = 144x^{-6}

f'(x)^2 = \frac{144}{x^6}

Take square root of both sides

f'(x) =\± \sqrt{\frac{144}{x^6}}

f'(x) = \±\frac{12}{x^3}

Split:

f'(x) = \frac{12}{x^3} or f'(x) = -\frac{12}{x^3}

To solve fo f(x), we make use of:

f(x) = \int {f'(x) } \, dx

For: f'(x) = \frac{12}{x^3}

f(x) = \int {\frac{12}{x^3} } \, dx

Integrate:

f(x) = \frac{12}{2x^2} + c

f(x) = \frac{6}{x^2} + c

We understand that it passes through (x,y) = (1,-2).

So, we have:

-2 = \frac{6}{1^2} + c

-2 = \frac{6}{1} + c

-2 = 6 + c

Make c the subject

c = -2-6

c = -8

f(x) = \frac{6}{x^2} + c becomes

f(x) = \frac{6}{x^2} -8

For: f'(x) = -\frac{12}{x^3}

f(x) = \int {-\frac{12}{x^3} } \, dx

Integrate:

f(x) = -\frac{12}{2x^2} + c

f(x) = -\frac{6}{x^2} + c

We understand that it passes through (x,y) = (1,-2).

So, we have:

-2 = -\frac{6}{1^2} + c

-2 = -\frac{6}{1} + c

-2 = -6 + c

Make c the subject

c = -2+6

c = 4

f(x) = -\frac{6}{x^2} + c becomes

f(x) = -\frac{6}{x^2} + 4

3 0
3 years ago
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