The sum of 3 consecutive even integers is 18
1 answer:
Answer:
4,6,8
Step-by-step explanation:
Let x = 1st even integer
x+2 =2nd even integer
x+4 =3nd even integer
x+ x+2 + x+4 = 18
Combine like terms
3x+6 = 18
Subtract 6 from each side
3x+6-6=18-6
3x= 12
Divide by 3
3x/3 =12/3
x = 4
x+2 = 6
x+4 = 8
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so if it's going to 6 it should be 4 adding 2
Answer:
3/4
Step-by-step explanation:
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3*4=12
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