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2 years ago

170 What is the mZBAC?

Mathematics

1 answer:

Westkost [7]2 years ago

3 0

Answer:

m<BAC = 85°

Step-by-step explanation:

The measure of an inscribed angle is half the measure of its intercepted arc.

m<BAC = 170°/2

m<BAC = 85°

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Use the grouping method to factor the polynomial below completely. x - 4x² + 3x - 12

N76 [4]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Pediatricians work an average of 48 h per week. The standard deviation is 12 hours. What percentage of pediatricians work more t

cricket20 [7]

Answer: 2.28 %

Step-by-step explanation:

Given : Mean : $\mu=\ 48$

Standard deviation : $\sigma= 12$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 72

$z=\dfrac{72-48}{12}=2$

The p-value = $P(2$

$1-0.9772498=0.0227502\approx0.0228$

In percent, $0.0228\times100=2.28\%$

Hence, the percentage of pediatricians work more than 72 h per week = 2.28 %

4 0

3 years ago

Need help with math problem if do 5 stars

Harrizon [31]

Answer:

the answer is $41 the cost of beans

4 0

2 years ago

Please Help Me

wel

X = 3
y = -1

get the x or y by itself first (second eq. is easier)
So, x + 2y = 1
-2y -2y
Now we get:
x = -2y +1 Plug it into the other equation.

2x + 3y = 3
2(-2y +1) + 3y = 3
-4y + 2 + 3y = 3
-1y +2 = 3
+1y -3 -3 +1 y

y = -1 (plug into either eq to get x)

x + 2y = 1
x+2(-1) = 1
x-2=1
+2 +2

x = 3

6 0

3 years ago

how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

3 years ago

170 What is the mZBAC?​

170 What is the mZBAC?