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SIZIF [17.4K]
2 years ago
6

The coordinates of point A are (-5,p) and the coordinates of point B are (7,10). The midpoint of the linear segment AB has coord

inates (q,3). Find the value of q and p.​
Mathematics
1 answer:
Aleks04 [339]2 years ago
3 0

Answer:none of the options is correct

the answer is (5,0)

Step-by-step explanation:

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HELP ASAP
hichkok12 [17]

Answer:

A. 108 in^2

B. 144 in^2

C. 36 in^2

Step-by-step explanation:

7 0
2 years ago
Use the Binomial Theorem to expand each binomial (5x-4y)^3
jek_recluse [69]
You should know that:

(a+b)(a+b)(a+b)

=a(a+b)(a+b)+b(a+b)(a+b)

=a(a²+2ab+b²)+b(a²+2ab+b²)

=a³+2a²b+ab²+a²b+2ab²+b³

=a³+3a²b+3ab²+b³

-----------------

If a=5x and b=-4y

(5x+(-4y))³

=(5x-4y)³

=(5x)³+3(5x)²(-4y)+3(5x)(-4y)²+(-4y)³

=125x³+3(25x²)(-4y)+15x(16y²)-64y³

=125x³+75x²(-4y)+240xy²-64y³

=125x³-300x²y+240xy²-64y³
5 0
3 years ago
Consider the function below. f(x) = 6x tan x, −π/2 < x < π/2 (a) find the vertical asymptote(s). (enter your answers as a
Molodets [167]

Answer: Does not exist.

Step-by-step explanation:

Since, given function,  f(x) = 6x tan x, where −π/2 < x < π/2.

⇒ f(x) = \frac{6x sin x}{cosx}

And, for vertical asymptote,  cosx= 0

⇒ x = π/2 + nπ where n is any integer.

But, for any n x is does not exist in the interval ( -π/2, π/2)

Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.


5 0
3 years ago
Read 2 more answers
Fill in the blank to complete the sentence. A square with area 49 cm² has perimeter cm ok 2 Asquare with area 49 cm? has perimet
klasskru [66]

Answer:

7 cm

Step-by-step explanation:

it is a square so sqrt(49)=7, and the side lengths are 7

7 0
2 years ago
There are 15 questions in this quiz. Im sorry if im putting too much pressure on yall
nika2105 [10]

Answer:

86

Step-by-step explanation:

i dont really kbow why but i think it 86

4 0
2 years ago
Read 2 more answers
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