(a)

or, via symmetry

____________
(b)
By the chain rule:

For polar coordinates, x = rcosθ and y = rsinθ. Since
<span>r = 3 + 2cosθ, it follows that

Differentiating with respect to theta

2/3 is the slope
____________
(c)
"</span><span>distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3
A</span>ngle θ and r are related via <span>r = 3 + 2cosθ, so implicitly differentiating with respect to time
</span><span />
Answer:
2=2
Step-by-step explanation:
Answer:
Graph 1 is not proportional
Graph 2 is proportional - y is 2 times x
Step-by-step explanation:
In graph 1, there is no x-y correlation
In graph 2, there is, when x=1, y=6
when x=2, y=12. Therefore, when x=3 y would equal 18.