All categories

3 years ago

Work out the circumference of the circle when the radius is 6mm and give the answer in terms of pie.

1 answer:

4 0

_______________________________

Hey!!

Solution,

Radius(r)= 6 mm

Circumference of circle=?

Now,

Circumference of circle=2 pie r

 =2*pi*6

So the answer is 12 pie.

Hope it helps...

Good luck on your assignment

You might be interested in

Consider a steel ball floating on the surface of mercury in a half-filled container. What happens when the rest of the container

Helen [10]

Answer

The steel ball will be caught up in between the mercury and water medium.

Step-by-step explanation:

Mercury with a density of 13546 kg/m^3

water with a density of 1000 kg/m^3
Steel with a density of 8050 kg/m^3

From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.

The steel ball will be caught in between both mixtures as the density of steel is 8050 kg/m^3.Which is more than Water but less than Mercury.

8 0

3 years ago

S+2t=6. 3s-2t=2 Using elimination

Ludmilka [50]

For the first one, I will solve for t.
s + 2t = 6, first we isolate the t variable,
2t = -s + 6, divide both sides by 2,
t = -s/2 + 3, < There's your answer for 1!

Here's the second one,
3s - 2t = 2, subtract 3s from both sides,
-2t = 2 - 3s, divide both sides by -2,
t = -1 + 3s/2 < There's your second answer!

6 0

2 years ago

Use the right triangular prism shown to answer the following questions.

Tju [1.3M]

Answer:

168cm is the right answer

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Blank - 5.27 = 2.99 literally forgot how decimals work

bulgar [2K]

Answer:

8.26

Step-by-step explanation:

you can solve this by putting x for blank

x-5.27=2.99

solve for x

x-5.27+5.27=2.99+5.27

x=8.26

3 0

2 years ago

Read 2 more answers

Determine whether the improper integral converges or diverges, and find the value of each that converges.

kiruha [24]

Answer:

Diverges

Step-by-step explanation:

For the improper integral to converge the limit must exist, if the limit does not exist or is infinite the integral diverges;

$\int\limits^a_b {(2x+4)/x^2+4x+5} \, dx$ #

Where a and be is infinity

The solution of this is infinity and therefore the integral diverges because the first expression is undefined because ∞/∞, the second term is 4·∞ which is infinity and infinity added to any number is infinity

3 0

3 years ago