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Ilia_Sergeevich [38]
3 years ago
15

Give the values a, b, and c needed to write the equations standard form. 2/3(x-4)(x+5)=1

Mathematics
1 answer:
Verizon [17]3 years ago
6 0
The standard form of the quadratic equation is given by:
 ax ^ 2 + bx + c
 What we must do in this case is to rewrite the given equation.
 We have then:
 2/3 (x-4) (x + 5) = 1
 (x-4) (x + 5) = 3/2
 (x ^ 2 + 5x-4x-20) = 3/2
 2x ^ 2 + 2x-40 = 3
 2x ^ 2 + 2x-43 = 0
 Thus, the values of a, b and c are:
 a = 2
 b = 2
 c = -43
 Answer: 
 a = 2
 b = 2
 c = -43
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Answer:

1\frac{1}{27}

Step-by-step explanation:

\frac{8}{9}÷\frac{6}{7}

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3 years ago
What is 3,000 is 1/10 of
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Answer:

30000

Step-by-step explanation:

3000 / (1/10) = w

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30000*1/10 = 3000

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4 0
3 years ago
Which of the following statements are true about scalar multiplication of matrices?
Greeley [361]

Scalar multiplication of a matrix refers to the multiplication of all the elements of the matrix by an ordinary number which is called a scalar.

From the given options the statements which are true about scalar multiplication of matrices are;

a)       You can multiply a matrix of any size by a scalar.

b)      For any matrix A, 1 × A = A.

c)       Scalar multiplication is a shortcut for repeated addition of the same matrix.

3 0
3 years ago
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Which of the following expressions can be factored by grouping? (Select all that apply.)
Greeley [361]

Answer:

Options (3), (4) and (5)

Step-by-step explanation:

1). a² - 9a + 7ab + 63b

  = a(a - 9) + 7b(a + 9)

  Now we can not solve this problem further.

  Therefore, can't be factored by grouping.

2). 3a + 4ab - b - 12

   = a(3 + 4b) - 1(b - 12)

   We can't solve it further.

   Therefore, can't be factored by grouping.

3). ab + 6b - 2a - 12

   = b(a + 6) - 2(a + 6)

   = (b - 2)(a + 6)

  We can be factored this expression by grouping.

4). x³ + 9x²+ 7x + 63

   = x²(x + 9) + 7(x + 9)

   = (x² + 7)(x + 9)

   Therefore, the given expression can be factored by grouping.

5). ay² + a - y² - 1

  = a(y² + 1) - 1(y² + 1)

  = (a - 1)(y² + 1)

  This expression can be factored by the grouping method.

Options (3), (4) and (5) are the correct answers.

3 0
3 years ago
Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.
VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

4 0
2 years ago
Read 2 more answers
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