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lutik1710 [3]
3 years ago
13

Peter attends 6 lessons each week . A year he attends 52 weeks. But he missed 5 classes how many lessons did he attend during th

e year?
Mathematics
1 answer:
VMariaS [17]3 years ago
4 0
You are given the information that he takes six lessons per week. First we will calculate the total lessons he could potentially take per year.

6 • 52 = 312

He could potentially take 312 lessons in one year.

Now that you know this information, you simply subtract the days he missed from that total.

312 - 5 = 307

Your final answer: Peter took 307 lessons during the year.
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Passing through (-2,1 ) and perpendicular to<br> 4x + 7y + 3 = 0.
Lunna [17]

Answer:

<h2>7x - 4y + 18 = 0</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

========================================

Let

k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2

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We have the equation of a line in a general form (Ax + By + C = 0)

Convert it to the slope-intercept form:

4x+7y+3=0             <em>subtract 7y from both sides</em>

4x+3=-7y         <em>divide both sides by (-7)</em>

-\dfrac{4}{7}x-\dfrac{3}{7}=y\to m_1=-\dfrac{4}{7}

Therefore

m_2=-\dfrac{1}{-\frac{4}{7}}=\dfrac{7}{4}

We have the equation:

y=\dfrac{7}{4}x+b

Put the coordinates of the point (-2, 1) to the equation, and solve for <em>b</em> :

1=\dfrac{7}{4}(-2)+b

1=-\dfrac{7}{2}+b     <em>multiply both sides by 2</em>

2=-7+2b           <em>add 7 to both sides</em>

9=2b            <em>divide both sides by 2</em>

[te]x\dfrac{9}{2}=b\to b=\dfrac{9}{2}[/tex]

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Convert to the general form:

y=\dfrac{7}{4}x+\dfrac{9}{2}         <em>multiply both sides by 4</em>

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0=7x-4y+18

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D.

Step-by-step explanation:

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2 years ago
A bus company has contracted with a local high school to carry 450 students on a field trip. The company has 18 large buses whic
Galina-37 [17]

Answer:

The answer is below

Step-by-step explanation:

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After plotting the graph, the minimum solution to the graph are at:

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At point D:

F(x, y) = 225(18) + 100(2) = $4250

The minimum cost is at point C(10, 10) which is $3250

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