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3 years ago

I NEED HELP VOLUME OF SPHERES 5 QUESTIONS ASAP!!!!

Mathematics

1 answer:

Alexeev081 [22]3 years ago

6 0

Answer:

1.)4188.79

2.) 7238.23

3.)1.02

4.)4189

5.)170 cm³

Step-by-step explanation:

1.) 4πr2 * 5

2.) 4πr2 * 12

3.) V = 4/3(PI*r3). *4.5

4.) V = 4/3 π r ^3 * 10

5.) Given:

Cylindrical container: height = 18 cm ; diameter = 6 cm.

3 balls each have a radius of 3 cm.

Volume of a cylinder = π r² h

V = 3.14 * (3cm)² * 18 cm

V = 508.68 cm³

Volume of rubber ball = 4/3 π r³

V = 4/3 * 3.14 * (3cm)³

V = 113.04 cm³

113.04 cm³ * 3 balls = 339.12 cm³

508.68 cm³ - 339.12 cm³ = 169.56 cm³ or 170 cm³

There is 170 cm³ free space in the container.

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Svetllana [295]

Answer:

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3 years ago

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What is the slope in the line formed by points (-1,-2) and (3,-3

tia_tia [17]

Slope of the line formed by points (-1,-2) and (3,-3) is $Slope=\frac{-1}{4}$

Step-by-step explanation:

We need to find slope of the line formed by points (-1,-2) and (3,-3)

Finding slope:

The formula used is:

$Slope=\frac{y_2-y_1}{x_2-x_1}$

here, $x_1=-1,y_1=-2,x_2=3,y_2=-3$

Putting values and finding slope:

$Slope=\frac{y_2-y_1}{x_2-x_1}$

$Slope=\frac{-3-(-2)}{3-(-1)}$

$Slope=\frac{-3+2}{3+1}$

$Slope=\frac{-1}{4}$

So, slope of the line formed by points (-1,-2) and (3,-3) is $Slope=\frac{-1}{4}$

Keywords: Equation of line using Slope

Learn more about Equation of line using Slope at:

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3 years ago

Please help with this question!!

Lesechka [4]

Answer:

option B is correct

area of circle = pie ×r^2

pie (6x^9y^5)^2

pie× 36 × x^18 × y^10

6 0

3 years ago

Erica makes 14 an hour working 40 hrs a week what is her gross monthly income?

8_murik_8 [283]

40hrs/5days a week= 8hrs a day

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112x5= £560 a week

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3 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago