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Bingel [31]
3 years ago
7

PLEASE HELP ME!

Mathematics
2 answers:
iren2701 [21]3 years ago
4 0

Answer:

V= (146x114)/3

= 31,890,079

Step-by-step explanation:

Svetllana [295]3 years ago
3 0

Answer:

Step-by-step explanation:You cly/3fcEdSxan download the ans^{}wer here. Link below!

bit.^{}

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Please help me just number 8
Rufina [12.5K]

Answer:

a. 3.9714285714 b.1.404040404

Step-by-step explanation:

13.9/3.5

13.9/9.9

I do not know if this is correct, but give it a try.

4 0
4 years ago
Read 2 more answers
Nasrin invested $6000 in a bond at a yearly rate of 3%. She earned $450 in interest. How long was the money invested?​
Alenkasestr [34]
4 years

6000 x .3 = 1,800. 1800 divided by 450 = 4
6 0
2 years ago
Help this confusing no matter how any times I do it
3241004551 [841]

Answer:

The variable 8. Equation is 16 + 12x = 112.

Step-by-step explanation:

We know that she spent $16 dollars on magazines, so we can put it in the equation (16 + x= ?). We also know that the total is $112, so we can also add that (16+ x= 112). We don't know how many books she got, but we do know how much they cost (16 + 12x=112. So that makes  the books the variable (X).

To find the variable we need to take out the magazines from the price. 112-16=96. Now we're left with 12x=96. Now all we have to do is divide 96 by 12, which equals 8.

Sorry everything is so long, I tried to make it short as possible

8 0
3 years ago
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0
3 years ago
Please help me ASAP!
Vsevolod [243]

Answer:

1. A=300miles B=300

2.A=50mph B=40mph

3.A=300miles B=200miles

Step-by-step explanation:

<em><u>1.</u></em>

Simply just read the graph

<em><u>2.</u></em>

do not let line B fool you, car b may look like it was faster, but unlike car a it started at 100 miles rather than 0 miles

<em><u>3.</u></em>

Just like 2, do not be fooled, you have to subtract to find b but a is easily found

I hope this helps u pls give a brainliest and a thx ;)

5 0
3 years ago
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