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konstantin123 [22]
3 years ago
7

Create a variable expression that represents the word phrase: twelve times a number

Mathematics
1 answer:
ASHA 777 [7]3 years ago
7 0
12n or 12
\times n
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What is the square number of 13 27 81 21 43 48 23 39 45
Setler [38]

The given numbers are 13, 27, 81, 21,43, 48,23,39,45.

Square number is that number which is a perfect square means if you multiply a number by itself the number you obtained is a perfect square i.e it's square root is a natural number.

√13=not a natural number

√27=√3×√3×√3=3√3=irrational number

√81=√9×√9=9=a natural number

√21=not a natural number

√43=not a natural number

√48=4√3=not a natural number

√23=not a natural number

√39=not a natural number

√45=3√5=not a natural number

So, out of following numbers 13 27 81 21 43 48 23 39 45→81 is the only square number.

8 0
3 years ago
Read 2 more answers
125% of what number is 264
neonofarm [45]
Let, the number = x
x * 125 / 100 = 264
x = 264*100 / 125
x = 26400/125
x = 211.2

So, that number & your final answer is 211.2

Hope this helps!
8 0
3 years ago
Write 3+9+27+81+243+729 in stigma notation
Ainat [17]

Answer:

546

Step-by-step explanation:

4 0
3 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
Please help asap<br> WILL GIVE BRAINLIEST
dexar [7]
Sorry I can’t see the picture it’s blurry for me
8 0
3 years ago
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