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ryzh [129]
3 years ago
7

In the figure,  x ∥ y and a is a transversal that crosses the parallel lines.

Mathematics
1 answer:
Dominik [7]3 years ago
8 0
Here, exterior angles are 1, 2, 7 & 8 as they are outside the parallel lines, & among them, alternates are: 1 with 7 and 2 & 8. 1 & 7 is not in option but 2 and 8 is there in C

In short, Your Answer would be Option C

Hope this helps!
You might be interested in
Kyle held a balloon 8 feet off the ground, straight above his head. Ava is standing 15 feet directly to the right of Kyle.
Mazyrski [523]

Complete Question:

Kyle held a balloon 8 feet off the ground, straight above his head. Ava is standing 15 feet directly to the right of Kyle.

Write an equation using the Pythagorean Theorem to find the value of x.  

How far are Ava's feet from the balloon?

Answer:

Ava's feet is 17ft away from the balloon

Step-by-step explanation:

Given

height = 8ft

distance = 15ft

The attached image represents the scenario

Using Pythagoras theorem (from the attachment), we have:

x^2 = 8^2 + 15^2

x^2 = 64 + 225

x^2 =289

Take square roots of both sides

x = \sqrt{289

x = 17

6 0
3 years ago
The bill for dinner was $34. You left $50 to pay for the meal and tip the server. What percent of the meal did you leave as a ti
9966 [12]

Answer:

16

Step-by-step explanation:

50 - 34 = 16

6 0
3 years ago
The local fitness center offers membership discounts for hospital employees. According to the membership brochure, you will rece
Liono4ka [1.6K]

Answer:

48.75$

Step-by-step explanation:

Since the original price is 65$ and you are getting 25% off, you would now be paying 75% of the original price.

65*75%=48.75

_______________________________________________________

You could also take the amount of discount you're getting...

65*25%

and then subtract the amount of discount your getting from the original price

65-(65*25%) = 48.75

7 0
2 years ago
Graph the first six terms of a sequence where a1=5 and r=1.25
emmainna [20.7K]
The sequence above is geometric progression. 
The nth term of such sequence is given by;

Tn = ar∧(n-1),
Where a⇒first term and
            r⇒common ratio

So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5 
      2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
      3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
       4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
       5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
       6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
7 0
3 years ago
Prove the divisibility of the following numbers:
ratelena [41]

Make use of prime factorizations:

16^5+2^{15}=(2^4)^5+2^{15}=2^{20}+2^{15}

Both terms have a common factor of 2^{15}:

16^5+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33

- - -

The second one is not true! We can write

15^7+5^{13}=(3\cdot5)^7+5^{13}=3^7\cdot5^7+5^{13}

Both terms have a common factor of 5^7:

15^7+5^{13}=5^7\left(3^7+5^6\right)

Since 30=5\cdot6, and 5\mid5^7, we'd still have to show that 5^6(3^7+5^6) is a multiple of 6. This is impossible, because 6=3\cdot2 and there is no multiple of 2 that can be factored out.

4 0
2 years ago
Read 2 more answers
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