All categories

3 years ago

In the figure, x ∥ y and a is a transversal that crosses the parallel lines.

Mathematics

1 answer:

Dominik [7]3 years ago

8 0

Here, exterior angles are 1, 2, 7 & 8 as they are outside the parallel lines, & among them, alternates are: 1 with 7 and 2 & 8. 1 & 7 is not in option but 2 and 8 is there in C

In short, Your Answer would be Option C

Hope this helps!

You might be interested in

I WILL MARK BRAINLIEST

ICE Princess25 [194]

First one is : D (6)
Second one is : B (1/3)

Hope this helps!
Please give Brainliest!

5 0

2 years ago

If the height of the tree trunk is 13 feet and the radius is 1.5 feet what is the volume in cubic feet round to the nearest 10th

Mumz [18]

Answer:

91.8 feet^3

Step-by-step explanation:

We can find out the area of a circle and then multiple that by the height to get the volume of the tree trunk (which is a cylinder).

Area of circle formula: pi x r^2

3.14 x 1.5^2 = 7.065

Now we can multiple it by the height and round to the nearest 10th.

7.065 x 13 = 91.845

91.845 -> 91.8

Hope this helps! Brainliest?

6 0

2 years ago

Read 2 more answers

3n+22 +2n+38=180 m angle

s344n2d4d5 [400]

3n+2n= 5n
22+38=60
180-60=60
60=5n
n=12

8 0

3 years ago

For every 3 laps that Jackie swims, Ronnie swims 4 laps. During practice, they swam a combined total of 63 laps. How many laps d

Flura [38]

Answer:

36 laps Ronnie swim during practice .

Step-by-step explanation:

Let us assume that the laps that Ronnie swims be x .

Let us assume that the laps that Jackie swims be y .

As given

For every 3 laps that Jackie swims, Ronnie swims 4 laps.

i.e

3 × laps that Ronnie swims = 4 × laps that Jackie swims

3 × x = 4 × y

3x = 4y

Equation becomes

x + y = 63

Thus by using 3x = 4y .

$y = \frac{3x}{4}$

Thus

$x +\frac{3x}{4} = 63$

4x + 3x = 63 × 4

7x = 252

x = 36

Put the value of x in the equation x + y = 63

36 + y = 63

y = 63 - 36

y = 27

Therefore the 36 laps Ronnie swim during practice .

4 0

3 years ago

Hello I need help Finding the probability

Stolb23 [73]

Each petal of the region $R$ is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length $5\sqrt2$ , which implies the segment is subtended by an angle of $\dfrac\pi2$ . This means the area of the segment is

$\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}$
$\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2$

This means the area of one petal is $\dfrac{25\pi}2-25$ , and the area of $R$ is four times this, or $50\pi-100$ .

Meanwhile, the area of $G$ is simply the area of the square minus the area of $R$ , or $10^2-(50\pi-100)=200-50\pi$ .

So

$\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1$
$\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2$
$\mathbb P((X=R)\land(X=G))=0$ (provided these regions are indeed disjoint; it's hard to tell from the picture)
$\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1$

4 0

3 years ago