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3 years ago

In the figure, x ∥ y and a is a transversal that crosses the parallel lines.

Mathematics

1 answer:

Dominik [7]3 years ago

8 0

Here, exterior angles are 1, 2, 7 & 8 as they are outside the parallel lines, & among them, alternates are: 1 with 7 and 2 & 8. 1 & 7 is not in option but 2 and 8 is there in C

In short, Your Answer would be Option C

Hope this helps!

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The contrapositive of p q is:

Kay [80]

Some symbols are missing. I'm assuming you meant to put in a horseshoe symbol like so $p \supset q$

If so, then the contrapositive of that would be $\sim q \supset \ \sim p$ which is the final answer.

The tilde sign $\sim$ means "not" so writing $\sim q$ means "not q" which is the complete opposite of q.

6 0

3 years ago

PLZ help me it's is sooo hard

Andreas93 [3]

I'm not sure for number one, but for number 2 the answer to that one is the second tallest on the chart or on the histogram. For number 3 I'm not sure because i cant see the numbers there too blurry. I'm sorry but i hope i got the second one correct.

3 0

3 years ago

Whats 1+1 ita just to hard im trying but i can't figure it out

Nat2105 [25]

Answer: 25

Step-by-step explanation:

because its funnier than 24.

3 0

3 years ago

#2 Q is between P and R. Find PR.<br> 6x + 4<br> 3x<br> 3x tc<br> P<br> R<br> Q<br> 14x - 6 6-

otez555 [7]

Answer:

PR=22

Step-by-step explanation:

3x+6x+4=14x-6

9x+4=14x-6

10=5x

x=2

Plug in

3(2)

6(2)+4

12+4

16+6

So the bottom should equal 22

14(2)-6

28-6

Hope this helps

Brainliest would be appreciated

8 0

3 years ago

Use the function below to find f(1). f9t0=4

ExtremeBDS [4]

The value of the F(1) is 1/2 option (C) is correct after plugging the value of t = 1 in the provided function.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is attached in the picture please refer to the picture.

We have a function:

$\rm F(t) = 4\dfrac{1}{2^{3t}}$