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Mrac [35]
3 years ago
10

What is the value of n in the diagram below?

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Step-by-step explanation:

Picture############

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My question is in the picture pls help
Semenov [28]

Answer:

The answer is B. 38.25

Step-by-step explanation:

4.5*8.5

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Consider the equation below.
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I hope it will help u.......

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I will give brainliest if u answer these two questions
Vitek1552 [10]

Answer:

1) 5 1/8

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Dr,Goode prescribes 0.2 grams of cold medicine for Donald. This medicine comes in tablets that are 0.5 grams or 0.05 grams. Shou
e-lub [12.9K]

Using proportions, it is found that Donald should order 4 of the 0.05 gram tablets.

  • This question is solved by proportions, using a <em>rule of three</em>.
  • 4 tablets are needed, and they should combine for 0.2 grams. How many grams is there going to be on one tablet?

The <em>rule of three</em> is:

1 tablet - x grams

4 tablets - 0.2 grams

Applying cross multiplication:

4x = 0.2

x = \frac{0.2}{4}

x = 0.05

Donald should order 4 of the 0.05 gram tablets.

For more on proportions, you can check brainly.com/question/24372153

7 0
2 years ago
Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0
3 years ago
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