The sweatshirt size which the vendor should bring more of by virtue of that which is most likely to be sold is; Choice A; Extra-large.
<h3>Which sweatshirt size should the vendor bring more of?</h3>
If follows from the task content that the
ratio of extralarge shirts sold relative to the quantity he had to sell is
= 99/108
= 11/12,
This is a ratio which is larger than any other shirt.
Consequently, the vendor must bring more of the X-large shirts to avoid running out of them.
Read more on ratios;
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Answer:
1.27410595×1020
Step-by-step explanation:
Answer + Step-by-step explanation:
<u>24 + 7 and 9×(24+7)</u>
31 and 9 x (31)
31 and 279
the number is multiplied by 9
<u>12 - 7 and 4x(12-7)</u>
5 and 4 x (5)
5 and 20
the number is multiplied by 4
<u>3×(21 + 4) and 21 + 4</u>
3 x (25) and 25
75 and 25
the number is multiplied by 3
making the left side 3 times larger
<u>40 × 5 and 40 × 20</u>
200 and 800
1 lb= 16 oz
3/4 of 16=12
therefore Ms. Winn bought 12 oz of grapes
Answer:
Longer than 27.7 minutes.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The slowest quarter of customers will require longer than how many minutes (to the nearest tenth) for a simple haircut?
Longer than the 100 - 25 = 75th percentile of times, which is X when Z has a pvalue of 0.75. So X when Z = 0.675. So
So
Longer than 27.7 minutes.
