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Ksivusya [100]
4 years ago
10

What is measure of side A?

Mathematics
1 answer:
Ira Lisetskai [31]4 years ago
8 0

<u>Answer:</u>

The correct answer option is c. a = 11.94.

<u>Step-by-step explanation:</u>

We are given a right angles triangle with an angle ABC equal to 58 degrees and side length AC known to be equal to 19.1.

We are supposed to find the length of side a.

Side AC, opposite to angle ABC, will be the perpendicular and BC will be the base so we will use the formula of tan to find b.

tan 58 = \frac{19.1}{a}

a = \frac{19.1}{tan 58}

a=11.94

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Step-by-step explanation:

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8 0
4 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-10, 8) and
vlada-n [284]

Answer:

slope=3

Step-by-step explanation:

Use the following equation the find the slope:

\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{rise}{run}

Rise over run is the change in the y-axis over the change in the x-axis from one point to the other. This is also known as the "slope". Insert the known values:

(-10_{x1},8_{y1})\\\\(-15_{x2},-7_{y2})\\\\\\\frac{-7-8}{-15-(-10)}\\\\\frac{-7-8}{-15+10}

Solve:

\frac{-7-8}{-15+10}=\frac{-15}{-5}

Simplify. Two negatives make a positive:

\frac{-15}{-5}=\frac{15}{5}

Simplify fraction by dividing top and bottom by 5:

\frac{15}{5}=\frac{3}{1}  =3

The slope is 3.

:Done

8 0
3 years ago
Suppose students are independent from one another. 63% of students are using Mr. Martin's new social media app, Mar-tin-stagram.
vitfil [10]

Answer:

Probability that both of them use it = 0.3945

Step-by-step explanation:

Given:

Student use app = 63%

Number of chosen student = 2

Computation:

Assume total number of student = 100%

So, probability that both of them use it.

⁶³C₂ / ¹⁰⁰C₂

\frac{\frac{63!}{2! 61!} }{\frac{100!}{2! 98! } } \\\\\frac{63\times 62}{100 \times 99} \\\\\frac{3,906}{9,900} \\\\0.3945

Therefore, probability that both of them use it = 0.3945

4 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
Is negative three a perfect cube?
erik [133]

No, it is not a perfect cube. A perfect cube is a number that is obtained when you cube an integer. For example, 8 (cube of 2), 27 (cube of 3) and 64 (cube of 4). Since -3 cannot be obtained by cubing an integer, it is not a perfect cube.

6 0
3 years ago
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