Answer: 1 / 2 x2 / 1 1 / 3 = 0.3333333333
Step-by-step explanation:
Divide: 11 / 2 = 5.5
Multiple: the result of step No. 1 * 2 = 5.5 * 2 = 11
Divide: the result of step No. 2 / 11 = 11 / 11 = 1
Divide: the result of step No. 3 / 3 = 1 / 3 = 0.33333333
2. 25°
3. 155°
4. 25°
8. 90°
7. 25°
9. 65°
Answer:
4cm
Step-by-step explanation:
Answer:
Given statement: The number of gallons of water in the swimming pool x minutes after turning on the faucet is represented by :
.....[1]
The equation of straight line is represented by .....[2]
where
m represents the slope of line
and
b is the y-intercepts.
On comparing the equation [1] with [2] we get;
slope(m) = 24 and
y-intercept(b) = 285.
x-intercept defined as the graph crosses the x-axis i.e,
substitute the value of y =0 in [1] to solve for x;
0= 24x + 285
Subtract 285 from both sides we get;
-285 = 24x
Divide both sides by 24 we get;
x = -11.875
(a)
y= 24x + 285 where x is in minute.
You can see the graph of the equation as shown below.
(b)
Slope of the equation = 24
y-intercepts = 285
(c)
Since, x intercept is not applicable to this problem because value of x is negative as x represents the time(in minutes)
Answer:
The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.
Step-by-step explanation:
The complete question is:
The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.
Solution:
The (1 - <em>α</em>)% confidence interval for population mean is:
The margin of error for this interval is:
The critical value of <em>z</em> for 90% confidence level is:
<em>z</em> = 1.645
Compute the required sample size as follows:
Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.