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Triss [41]
4 years ago
7

How do i find the rate of change ?

Mathematics
1 answer:
NeTakaya4 years ago
5 0

Answer:

draw agraph and find the gradient

Step-by-step explanation:

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Find the volume of the composite solid. Round your answer to the nearest tenth.
mihalych1998 [28]

The volume of the composite solid is 645.97 cubic cm

<u>Step-by-step explanation:</u>

Given that,

The side of the cube = 8cm

Diameter of the hemisphere= 8cm

Radius = 4cm

Volume of cube = 8 x 8 x 8

= 512 cubic cm

Volume of hemisphere= (2/3) π (4 x 4 x 4)

= (2/3) π (64)

= (2/3) (3.14) (64)

= 133.97 cubic cm

Total volume = 512 + 133.97

= 645.97 cubic cm

The volume of the composite solid is 645.97 cubic cm

6 0
3 years ago
Joe is riding his bicycle. He rides for 3 hours at a speed of 4.8 kilometers per hour. For how many kilometers does he ride?
eduard

Answer:

14.4km

Step-by-step explanation:

<h2>Speed = distance / time </h2>
  • speed = 4.8 km/h
  • time = 3 hrs
  • distance = ?

Distance = speed  * time

Distance = 4.8 * 3 = 14.4km

5 0
2 years ago
Find the surface area of the cone whose radius and height are 2cm and 4cm respectively
Mademuasel [1]

Answer: Surface area of the cone is 40.85cm^2

Step-by-step explanation:

8 0
3 years ago
There are total of 63 bikes on a store.if the ratio of blue to red bikes is 4 to 5, how many of the bikes are blue
Triss [41]
4+5=9
63/9=7
7*4=28
7*5=35
If u add 28 and 35 the answer will be 63. I multiply the 4(blue bikes) to 7 and it equals to 28, so there are 28 blue bikes
8 0
4 years ago
Statistics Probability
andriy [413]

Answer:

Explained below.

Step-by-step explanation:

Denote the variable as follows:

M = male student

F = female student

Y = ate breakfast

N = did not ate breakfast

(a)

Compute the probability that a randomly selected student ate breakfast as follows:

P(Y)=\frac{n(Y)}{N}\\\\=\frac{198}{330}\\\\=0.60

(b)

Compute the probability that a randomly selected student is female and ate breakfast as follows:

P(F\cap Y)=\frac{n(F\cap Y)}{N}\\\\=\frac{121}{330}\\\\=0.367

(c)

Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

P(M|Y)=\frac{n(M\cap Y)}{n(Y)}\\\\=\frac{77}{198}\\\\=0.389

(d)

Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

P(Y|M)=\frac{n(Y\cap M)}{n(M)}\\\\=\frac{77}{154}\\\\=0.50

(e)

Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

P(M\cup N)=P(M)+P(N)-P(M\cap N)\\\\=\frac{n(M)}{N}+\frac{n(N)}{N}-\frac{n(M\cap N)}{N}\\\\=\frac{n(M)-n(N)-n(M\cap N)}{N}\\\\=\frac{154+132-77}{330}\\\\=0.633

(f)

Compute the probability of "is male and did not eat breakfast as follows:

P(M\cap N)=\frac{n(M\cap N)}{N}\\\\=\frac{77}{330}\\\\=0.233

4 0
3 years ago
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