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geniusboy [140]
2 years ago
6

Plzzzzzzzzz helppppp meeeee aaaaassssaaappp​

Mathematics
1 answer:
antoniya [11.8K]2 years ago
5 0

Answer:

1. the 3rd one

2. -9

3. 15

4. -8

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WILL MARK BRAINLIST FOR THE CORRECT ANSWER!!
stellarik [79]

Answer:

answer is A

Step-by-step explanation:

3*2=6

2pi/2=pi

8 0
2 years ago
A school needs 175 light bulbs.Bulbs come in packages of 15.How many packages should the school order?
kkurt [141]

Answer: 12 packages

Step-by-step explanation:

<em>Take 175 and divide it by 15</em>

<em>175/15</em>

<em>You will get 11.6</em>

<em>Since you are unable to order 11.6 packages you will need to order </em><em>12</em><em> packages to have enough lightbulbs.</em>

6 0
3 years ago
Read 2 more answers
You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perime
Anna71 [15]

Answer:

5 feet

Step-by-step explanation:

P = 2(w + l)

P = 34

l = w + 7

34 = 2 (w + w + 7)

34 = 2w + 2w + 14

34 - 14 = 4w

20 = 4w

w = 5 feet

Since l = w + 7

l = 5 + 7

l = 12 feet

5 0
2 years ago
How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6​
Ivahew [28]

9\cos(2t)=6\implies\cos(2t)=\dfrac23

Using the fact that cos is 2π-periodic, we have

\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi

That is, \cos(\theta+2n\pi)=\cos\theta for any \theta and integer n.

\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi

We get 2 solutions in the interval [0, 2π] for n=0 and n=1,

t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi

4 0
2 years ago
An ice cream store sells 28 flavors of ice cream. Determine the number of 4 dip sundaes.
katrin [286]

Answer:

20,475\ ways

Step-by-step explanation:

we know that

<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.

To calculate combinations, we will use the formula

C(n,r)=\frac{n!}{r!(n-r)!}

where

n represents the total number of items

r represents the number of items being chosen at a time.

In this problem

n=28\\r=4

substitute

C(28,4)=\frac{28!}{4!(28-4)!}\\\\C(28,4)=\frac{28!}{4!(24)!}

simplify

C(28,4)=\frac{(28)(27)(26)(25)(24!)}{4!(24)!}

C(28,4)=\frac{(28)(27)(26)(25)}{(4)(3)(2)(1)}

C(28,4)=20,475\ ways

5 0
2 years ago
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