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VMariaS [17]
3 years ago
9

I need the solution

Mathematics
1 answer:
Kazeer [188]3 years ago
5 0
24 beats per minute      
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1. What is the slope of the line in the graph show below?
bekas [8.4K]

What is the slope of the line in the graph show below? c1

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2 years ago
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Find the other endpoint of the line segment with the given endpoint and midpoint: endpoint(1.7, -4.6) midpoint (-7.5, 0.3).. (ne
Sergio [31]

Answer:

(- 16.7, 5.2 )

Step-by-step explanation:

let the coordinates of the endpoint be (x , y )

using the midpoint formula

consider the x- coordinate

\frac{1}{2}(x + 1.7) = - 7.5 ( multiply both sides by 2 )

x + 1. 7 = - 7.5 ( subtract 1.7 from both sides )

x = - 16.7

consider the y-coordinate

\frac{1}{2}(y - 4.6 ) = 0.3 ( multiply both sides by 2 )

y - 4.6 = 0.6 ( add 4.6 to both sides )

y = 5.2

endpoint = (- 16.7, 5.2 )


3 0
3 years ago
How many terms are in the binomial expansion of (3x + 5)9? 8 9 10 11
Stells [14]
The number of terms in the binomial expansion of (3x-5)^9 is 10
6 0
2 years ago
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Loni’s credit card statement for April showed a membership fee of $85, a late fee of $45, a finance charge of $7.45, and an over
Jlenok [28]

Answer:

$157.45

Step-by-step explanation:

All the amounts provided in the question are supposed to be added as a fee, so if you add all the numbers you would get $157.45.

4 0
3 years ago
What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

We conclude that there are 70+70=140 required subsets of S.

7 0
3 years ago
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