Answer:
<em>See Reasoning Below</em>
Step-by-step explanation:
To prove that AB = BL, or in other words AB ≅ BL, let us consider the triangles CED and BEL. If we were to prove they were congruent, then by CPCTC ( corresponding parts of congruent triangle are congruent ) DC ≅ BL. As AB ≅ DC by " Properties of Parallelogram " it would be that through transitivity, AB ≅ BL / AB = BL;
Now for " part 2 " we can consider that AB = DC, from part 1. If AB = BL, then AL = 2 ( AB ) by the Partition Postulate. AB = DC, so we can also say that AL = 2 ( DC ) - Proved
See attachment in statement reasoning form for part 1;
Answer:
Is it A
Step-by-step explanation:
thats the answer I got
The shape in the figure has 6 sides
The choice that describes the group the shape belongs to is (a) parallel sides, acute angles
<h3>How to determine the group of the shape?</h3>
From the figure, we have the following highlights
- The shape has 6 sides
- The direct opposite sides are equal
- The direct opposite sides are parallel
- The measure of angles between adjacent sides are less than 90 degrees i.e. acute angles
The above highlight mean that:
The shape belongs to parallel sides, acute angles group of shapes
Hence, Angela's conclusion is correct
Read more about polygons at:
brainly.com/question/1592456
<span>(-7) = e/3 + 14
Subtract 14 on both sides
-7 - 14 = e/3 + 14 - 14
-21 = e/3
Multiply by 3 on both sides
-21 * 3 = e/3 * 3
-63 = e</span>
The area of the trapezoid is 4.5cm
