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natulia [17]
3 years ago
11

Two non-simultaneous events have an equal likelihood of occurring (50%). If the events are independent of each other, what is th

e probability that they will both occur?
Mathematics
2 answers:
12345 [234]3 years ago
8 0
25% should be the answer, let me kno if its correct
Serggg [28]3 years ago
8 0

Answer: Probability that they will both occur is 25%.

Step-by-step explanation:

Since we have given that

There are two non simultaneous events.

Probability of each event = 50%

Since both are independent to each other.

Let A and B be two events.

We need to find the probability that they will both occur i..e P(A∩B).

As we know the rule of independence of events:

P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=0.5\times 0.5\\\\P(A\cap B)=0.25\\\\P(A\cap B)=25\%\\

Hence, Probability that they will both occur is 25%.

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Answer:

\left(\frac{x-2}{3} \right)^{2}+\left(\frac{y+1}{2} \right)^{2} = 1 (An ellipse)

Step-by-step explanation:

Let consider the following trigonometric identity:

\sin^{2}\theta + \cos^{2}\theta = 1

Each trigonometric function is cleared respectively in given parametric equations:

\cos \theta = \frac{x-2}{3} and \sin \theta = \frac{y + 1}{2}

The equivalent expression in rectangular form is:

\left(\frac{x-2}{3} \right)^{2}+\left(\frac{y+1}{2} \right)^{2} = 1

Which represents an ellipse.

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there are 4 lunch choices in a school cafeteria.The percentage of students that chose salad is 15%.If 300 students ate lunch, wh
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Step-by-step explanation:

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3 years ago
During his lunch hour, Matt asked 24 students how many after-school activities they participated in. This list shows
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As you can see, 4 of the 24 students don't partecipate in any activity. This clearly implies a ratio of 4:24, or 1:6.

We could infer that this ratio holds for the whole school, or even for all the boys and girls of that age.

That's the point of surveys and inferring: you gather data about a relatively small group, and then assume that the proportions you have are valid for a much larger group.

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3 years ago
Please help ive been on this question for days already!
Nataliya [291]

a. See image of the graph attached below.

b. The relation is a function

c. The domain is: {-1, 0, 1, 2, 3, 4, 5, 6, 7}

Range is: {-4, -3, 0, 5, 12}

<h3>How to Determine if a Relation is a Function?</h3>

If every x-value in a relation has exactly one y-value that corresponds to it, then the relation is a function.

A graph that has a U-shape with a minimum, that is the pointed U-shape is downwards, it means the relation has x-values that have exactly one y-value that corresponds to to it, therefore, the relation is a function.

a. To fill out the table, plug in the value of x into y = x² - 6x + 5:

When x = -1:

y = (-1)² - 6(-1) + 5 = 12

When x = 0:

y = (0)² - 6(0) + 5 = 5

When x = 1:

y = (1)² - 6(1) + 5 = 0

When x = 2:

y = (2)² - 6(2) + 5 = -3

When x = 3:

y = (3)² - 6(3) + 5 = -4

When x = 4:

y = (4)² - 6(4) + 5 = -3

When x = 5:

y = (5)² - 6(5) + 5 = 0

When x = 6:

y = (6)² - 6(6) + 5 = 5

When x = 7:

y = (7)² - 6(7) + 5 = 12

Thus, the graph has a minimum of -4.

b. The relation is a function because each x-value has exactly one y-value related to it.

c. The domain is: {-1, 0, 1, 2, 3, 4, 5, 6, 7}

Range is: {-4, -3, 0, 5, 12}

Learn more about function on:

brainly.com/question/10439235

#SPJ1

8 0
2 years ago
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