1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zalisa [80]
3 years ago
14

PLEASE HELP! Use triangle ROE to find the following. Leave the answer in fraction form (no decimal answer) SHOW WORK

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

tanθ = \frac{8}{15}

Step-by-step explanation:

By applying tangent rule in the given right triangle ROE,

tanθ = \frac{\text{Opposite side}}{\text{Adjacent side}}

tanθ = \frac{RO}{OE}

tanθ = \frac{8}{15}

Therefore, answer will be tanθ = \frac{8}{15}

You might be interested in
Subtract -5x+7 from 3x-2 set up your expression show your work
ruslelena [56]

3x-2

-(-5x+7)

☝️this is your equation

distribute your subtraction sign to -5x+7 and you get

3x-2

+5x-7

add everything together and you end up with

8x-9

3 0
4 years ago
Read 2 more answers
What is the standard form of 5x^2+5y^2-10x+20y-30=0
o-na [289]

5x^2+5y^2-10x+20y-30=0

We need to get the equation in square form

We apply completing the square method

5x^2-10x+5y^2+20y-30=0

Divide all the terms by 5

x^2-2x+y^2+4y-6=0

Group x  terms and y terms separately  

(x^2-2x)+(y^2+4y)-6=0

By completing the square method, we take half of coefficient of x  and square it

\frac{-2}{2} = -1

square it (-1)^2= 1

Add 1 on both sides

(x^2-2x+1)+(y^2+4y)-6=+1

\frac{4}{2} = 2

square it (2)^2= 4

Add 4 on both sides

(x^2-2x+1)+(y^2+4y+4)-6=0+1+4

Add 6 on both sides

(x^2-2x+1)+(y^2+4y+4)=6+1+4

Now factor both parenthesis

(x-1)^2+(y+2)^2=11

The equation of the circle is (x-1)^2+(y+2)^2=11

7 0
4 years ago
Please help question in the picture
zubka84 [21]
Its 56 I DID this you could only multiple the straight sides
7 0
3 years ago
What is the area of the triangle?<br> 7<br> 5<br> 4.<br> units2?
ruslelena [56]

Answer:

you should be able to do this

Step-by-step explanation:

8 0
3 years ago
How do you solve this? What is the answer????<br><br> Angle Similarity
lubasha [3.4K]

Answer:   How to solve for similar triangles? The SAS rule states that two triangles are similar if the ratio of their corresponding two sides is equal and also, the angle formed by the two sides is equal. Side-Side-Side (SSS) rule: Two triangles are similar if all the corresponding three sides of the given triangles are in the same proportion.

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • You found $6.60 on the ground at school, all in nickels, dimes, and quarters. you have twice as many quarters as dimes and 42 co
    7·1 answer
  • Change the fraction 7/12 to a decimal. Round your answer to the nearest thousandth. A. .600 B. 1.714 C. .583 D. 1.700 Mark for r
    7·1 answer
  • Decide whether JKLM is similar to NPRS. Explain your reasoning.
    7·2 answers
  • Each cabin had exactly 8 occupants. The number of occupants for all of the cabins was 208. How many cabins were there altogether
    15·1 answer
  • Shawn has a cherry tree in his yard. Currently the tree is 14 feet tall. That is 40% taller than it was when Shawn planted it. H
    13·1 answer
  • How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2?
    11·2 answers
  • The letters that form the word ALGEBRA are placed in a bowl. What is the probability of choosing a letter that is NOT B.
    14·2 answers
  • Jessica completed 21 math problems In 14 minutes at this rate how many math problems could complete in 30 minutes
    8·1 answer
  • Concert tickets cost $15 for general admission, but only $9 with a student ID. Ticket sales total $450. Write and graph an equat
    14·1 answer
  • The table below shows the amount of flour and eggs you need for making different-sized batches of cookies using the same recipe.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!