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Alekssandra [29.7K]
3 years ago
12

Subtract -5x+7 from 3x-2 set up your expression show your work

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0

Answer:

\large\boxed{(3x-2)-(-5x+7)=8x-9}

Step-by-step explanation:

(3x-2)-(-5x+7)\\\\=3x-2-(-5x)-7\\\\=3x-2+5x-7\qquad\text{combine like terms}\\\\=(3x+5x)+(-2-7)\\\\=8x-9

ruslelena [56]3 years ago
3 0

3x-2

-(-5x+7)

☝️this is your equation

distribute your subtraction sign to -5x+7 and you get

3x-2

+5x-7

add everything together and you end up with

8x-9

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I want to know the answer to an increase of 1.6% of $1252.00
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It’s easy!
Since you’re increasing 1.6% to $1252 you write the expression as:
=1252+1.6% of 1252
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That’s your final answer
4 0
3 years ago
What is 0.25% of 137
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Answer:

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Step-by-step explanation:

5 0
3 years ago
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Answer:

Step-by-step explanation:

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2 years ago
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
3 years ago
Is it more difficult to run up a ramp with a slope of 1/5 or a ramp with a slope of 5? Explain.
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a dlope of 1/5 is walkable; a slope of 5 is not without climbing gear.

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