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Sidana [21]
3 years ago
6

R is positive can someone simplify it ik it may actually be simple lol

Mathematics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

can you explain the question better

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Please help I have a sucky teacher and don’t know what to do
Katyanochek1 [597]

Answer:

  1, 4, 3, 6, 2, 7, 5

Step-by-step explanation:

The circle operator in f\circ g means that the function named on the left (f) operates on the result of the function named on the right (g). So, the notation

  (f\circ g)(x)

means

  f(g(x))

That is, g(x) is computed and used as input to the function f. When the function definitions are as shown, the evaluation proceeds in these steps.

  (f\circ g)(-4)\\\\=f(g(-4))\quad\text{write as function of a function}\\\\=f(-2(-4)^2)\quad\text{put -4 for x in $g(x)$}\\\\=f(-2(16))\quad\text{evaluate $(-4)^2$}\\\\=f(-32)\quad\text{evaluate $g(-4)$}\\\\=2(-32-1)\quad\text{put -32 for x in $f(x)$}\\\\=2(-33)\quad\text{first step evaluating $f(-32)$}\\\\=-66\quad\text{value of $(f\circ g)(-4)$}

__

If your step choices at the bottom are numbered 1 to 7 left-to right, then the sequence is as shown in the Answer section above.

4 0
3 years ago
Given: 3x+7+2(4x+1) = 3(x-1) -4 prove: x=-2
denis23 [38]

Answer:

x = -2, proven below.

Step-by-step explanation:

3x + 7 + 2(4x+1) = 3(x-1) - 4

3x + 7 + 8x + 2 = 3x - 3 - 4

9 + 11x = 3x - 7

16 + 11x = 3x

16 = - 8x

-2 = x

7 0
3 years ago
Please help !! Geometry homework. Will mark brainliest answer !
sergeinik [125]

For this case we have:


By trigonometric property we have:


Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}

Where:


Adjacent Leg = 12\\Hypotenuse = 13\\\alpha= x

Substituting:


Cosine(x)=\frac{12}{13}

Clearing x we have:


x =Cosine^{-1}(\frac{12}{13})

Thus, the equation is: x =Cosine^{-1}(\frac{12}{13})

Answer:


x =Cosine^{-1}(\frac{12}{13})


3 0
3 years ago
Pls help asap!!!! tysm guys!!
Delvig [45]

Answer:

C. 256 in2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Choose the inverse of y = x2 - 10x.
PilotLPTM [1.2K]

=Y2-10Y

We move all terms to the left:

-(Y2-10Y)=0

We add all the numbers together, and all the variables

-(+Y^2-10Y)=0

We get rid of parentheses

-Y^2+10Y=0

We add all the numbers together, and all the variables

-1Y^2+10Y=0

a = -1; b = 10; c = 0;

Δ = b2-4ac

Δ = 102-4·(-1)·0

Δ = 100

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

Y1=−b−Δ√2aY2=−b+Δ√2a

Δ‾‾√=100‾‾‾‾√=10

Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10

Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0

3 0
3 years ago
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