Since the radius of the semi circle is 10 cm then the diameter is 20 cm, when folded, its circumference is now 20, given the circumference find the radius of the cone. i guess
Volume = 1/3 πr2 (l2﹣r2)1/2
circumference = 20 cm = πD
D=6.363636364
Radius = 6.363636364/2 = 3.181818182
l = 10
vol = 100.51cm3
curved s.a = πrl
=99.96cm2
Answer:
I'm guessing C
Step-by-step explanation:
I don't think this is the correct way to answer it. But I litterly rotated it in my brain and got 7.5....
Step-by-step explanation:
-4 - 24 i
Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴ 
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180

Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°