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Elena-2011 [213]
2 years ago
9

What is the value of n In the equation below?

Mathematics
2 answers:
svetoff [14.1K]2 years ago
7 0

Answer:

2n + 6 = 2n + 10 \\ 2n - 2n = 10 - 6 \\ 0n = 4 \\  \\ { \boxed{ \boxed{ \tt{ \red{! \:  \: no \: solution}}}}}

elena55 [62]2 years ago
5 0
The answer is the letter B
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The Point Imperial is the highest point of the Grand Canyon and it is 8,800
Afina-wow [57]

Answer:

1222

Step-by-step explanation:

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3 0
2 years ago
The vertex of this parabola is at (-2, 5) (opens upward)
Rzqust [24]

Answer:

b.  y = 3(x+2)^2 + 5

Step-by-step explanation:

The vertex form of a parabola is

y = a(x - h)^2 + k    where (h, k) is the vertex.

Here  h = -2 and k = 5 so the following could be the required equation\;

y = 3(x+2)^2 + 5

7 0
3 years ago
1. Carter will install fencing all around the flat area of his
MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points (x_1,y_1) and (x_2,y_2) is given by the formula,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between A(3, 6) and B(3, -2) = \sqrt{(3-3)^2+(6+2)^2}

                                                               = 8 yards

Distance between B(3, -2) and C(-7, 4) = \sqrt{(3+7)^2+(-2-4)^2}

                                                                = \sqrt{136}

                                                                = 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = \sqrt{(-7+7)^2+(4+2)^2}

                                                                 = 6 yards

Distance between D(-7, -2) and E(-3, -2) = \sqrt{(-7+3)^2+(-2+2)^2}

                                                                   = 4 yards

Distance between E(-3, -2) and F(-3, -8) = \sqrt{(-3+3)^2+(-2+8)^2}

                                                                = 6 yards

Distance between F(-3, -8) and G(3, -8) = \sqrt{(-3-3)^2+(-8+8)^2}

                                                                 = 6 yards

Distance between G(3, -8) and H(10, -12) = \sqrt{(3-10)^2+(-8+12)^2}

                                                                   = \sqrt{49+16}

                                                                   = \sqrt{65}

                                                                   = 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = \sqrt{(10-10)^2+(-12-6)^2}

                                                                   = 18 yards

Distance between A(3, 6) and J(10, 6) = \sqrt{(10-3)^2+(6-6)^2}

                                                               = 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

                                              = 75 yards

Therefore, amount of fencing required = 75 yards

8 0
3 years ago
Find the equation (in terms of x ) of the line through the points (-1,4) and (2,-5)
marishachu [46]

Answer:

( 1 , -3 ) for every +1 on the x line you go -3 on the y I hope this is what you need

6 0
2 years ago
(m +n + 3) + (m +n + 4)
S_A_V [24]

2m+2n+7 is the correct answer

8 0
3 years ago
Read 2 more answers
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