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3 years ago

Please help me solve this question

Mathematics

1 answer:

finlep [7]3 years ago

8 0

(24·z^3)^2/(27·12·z) = (2^3·3·z^3)^2/(3^3·2^2·3·z) = (2^6·3^2·z^6)/(3^3·2^2·3·z) = 2^4·3^(-2)·z^5

a = 4 ; b = -2 ; c = 5

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Answer:

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Step-by-step explanation:

1. Substitute y = -3x +4 for y in the first equation

2x- (-3x+4) = 6

2. Combine like terms

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5x -4 +4 = 6+4

5x=10 Divide by 5 to isolate x

5x/5 =10/5

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3. Substitute in x into the 2nd equation to get y

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3 years ago

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