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iVinArrow [24]
3 years ago
5

Write a unit rate for the situation. $1.98 for 6 bananas

Mathematics
1 answer:
USPshnik [31]3 years ago
4 0
A unit rate is when you find a rate when one variable (or value) is equal to one.

Let's find the unit rate for the price of the bananas. 

1.98/6= 0.33

It is 33 cents for one banana. That is the unit rate. 

I hope this helps!
~kaikers
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4 years ago
Haben knows that the angle of elevation from the top of a rock formation to a stake in the ground 50 feet from its base is 42°.
Murrr4er [49]

Answer:

The height of the rock formation is 45.02\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

tan(42\°)=h/50

solve for h

h=50*tan(42\°)=45.02\ ft

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3 years ago
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Which is the most likely reason Ohio specializes in manufacturing transportation equipment?
My name is Ann [436]

Answer:

C

Step-by-step explanation:

Ohio's resources support manufacturing equipment.

6 0
4 years ago
A survey asked people of different ages whether they get their news by reading the paper. What is the probability that a person
Bingel [31]

C. 60%

The probability that a person surveyed is 40 or older and gets the news by reading the paper is 60%.

Step-by-step explanation:

In our case, we have to find the probability of a person getting their news by reading the paper. But we are given with a condition that the person must be 40 or older.

The survey is conducted among 80 people.

Number of people aged 40 or older = 40

No of people aged 40 or older and read paper = 24

Probability formula is the ratio of number of favorable outcomes to the total number of possible outcomes.

Probability of a person aged 40 or older reads a paper =

(No. of People aged 40 or older and read paper)/(No. of people aged 40 or older)

= 24/40

= 0.6

= 60%

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8 0
3 years ago
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Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
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