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MAXImum [283]
3 years ago
6

Z+17=23 what is the anwser​

Mathematics
1 answer:
aliina [53]3 years ago
8 0
The answer is 6 ,17+6=23
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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
2 years ago
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PLEASE HELP LAST PROBLEM I NEED HELP ON (Homework Help)
V125BC [204]

Answer:

a

Step-by-step explanation:

so the 2 in front means stretch 0f 2 the -3 in the parenthaesis means right 3 and the 1 means up 1

7 0
2 years ago
Which variable is most efficient to isolate?
mezya [45]

y in the first equation because y is already by itself. All you have to do is move the -3x to the other side.

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3 years ago
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What is the answer for number 11. Please
Zolol [24]
#11
Each roll is 9' long, 
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Each ribbon piece = 15", so number of ribbons per roll
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3 years ago
What is the answer of the equation 2(x+2)-7+x=27
mylen [45]

Answer:

x = 10

Step-by-step explanation:

Solve for x:

2 (x + 2) - 7 + x = 27

2 (x + 2) = 2 x + 4:

2 x + 4 + x - 7 = 27

Grouping like terms, 2 x + x - 7 + 4 = (2 x + x) + (4 - 7):

(2 x + x) + (4 - 7) = 27

2 x + x = 3 x:

3 x + (4 - 7) = 27

4 - 7 = -3:

3 x + -3 = 27

Add 3 to both sides:

3 x + (3 - 3) = 3 + 27

3 - 3 = 0:

3 x = 27 + 3

27 + 3 = 30:

3 x = 30

Divide both sides of 3 x = 30 by 3:

(3 x)/3 = 30/3

3/3 = 1:

x = 30/3

The gcd of 30 and 3 is 3, so 30/3 = (3×10)/(3×1) = 3/3×10 = 10:

Answer:  x = 10

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3 years ago
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