Answer:
swich the one attached to equation with the one attached to expression
Step-by-step explanation:
an equation need to have an equals sign, an expression doesnt.
a discrete graph (I had to look this one up)
Okay, so YZ = 3 cm. You have XM correct. And YM = 0.5.
Now, you have the midpoint M at the correct spot.
Use Pythagorean's theorem o find the length of AB. a² + b² = c² a=6, b=8.
6² = 36 8² = 64 36 + 64 = 100 AB = 10!
If AB = 10 then AM = 5 MB also = 5
If B is the midpoint of AC, C would be 12 rows down from A, and 16 columns to the right. The last spot where the line intersects.
There are your answers!
it is true; just work them out, you should get what they got :))
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
