Answer:
The most correct option for the recursive expression of the geometric sequence is;
4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2
Step-by-step explanation:
The general form for the nth term of a geometric sequence, aₙ is given as follows;
aₙ = a₁·r⁽ⁿ⁻¹⁾
Where;
a₁ = The first term
r = The common ratio
n = The number of terms
The given geometric sequence is 7, 14, 28, 56, 112
The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2
r = 2
Let, 't₁', represent the first term of the geometric sequence
Therefore, the nth term of the geometric sequence is presented as follows;
tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾
tₙ = t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁
∴ tₙ = 2·tₙ₋₁, for n ≥ 2
Therefore, we have;
t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.
Answer: y=-x-2
Slope intercept form is written as y=mx+b, with m being the slope and b being the y intercept.
The slope is negative one. To find the slope, use the formula y1-y2/x1-x2. When you substitute, you may get -4-1/2-(-3). When you solve it, you get -5/5, or -1.
To find the y intercept, look where the line crosses the y axis (vertical line). In the graph, it crosses as -2. Substitute these numbers into the equation and you get y=-1x-2 which can be simplified to y=-x-2.
Answer: No
Step-by-step explanation: No, they aren't. If you look at 5 and multiply (distribute) it to <u>negative</u> three you will end up with -15. And 15 is not equal to negative 15.
I hope this helps!
Answer:
=3a^3−2a^2−a−97
Step-by-step explanation:
Answer:
256 cm^2
Step-by-step explanation:
The area of the rectangle is the product of its length and width.
A = (16 cm)(10 cm) = 160 cm^2
The area of each triangle is half the product of its base and height.
A = (1/2)(16 cm)(6 cm) = 48 cm^2
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Then the area of the rectangle and 2 triangles is ...
160 cm^2 + 2(48 cm^2) = 256 cm^2
The area of the composite figure is 256 cm^2.