Answer:
2/7
Step-by-step explanation:
Since there are 18 males in the class
14 having A's and 4 not having A's
the probability would 4/14 which can be simplified to 2/7
I hope this helps^^
The answer is √
65 and the decimal form is 8.06
-- They're losing employees . . . so you know that the line will slope down, and
its slope is negative;
-- They're losing employees at a steady rate . . . so you know that the slope is
the same everywhere on the line; this tells you that the graph is a straight line.
I can see the function right now, but I'll show you how to go through the steps to
find the function. I need to point out that these are steps that you've gone through
many times, but now that the subject pops up in a real-world situation, suddenly
you're running around in circles with your hair on fire screaming "What do I do ?
Somebody give me the answer !".
Just take a look at what has already been handed to you:
0 months . . . 65 employees
1 month . . . . 62 employees
2 months . . . 59 employees
You know three points on the line !
(0, 65) , (1, 62) , and (2, 59) .
For the first point, 'x' happens to be zero, so immediately
you have your y-intercept ! ' b ' = 65 .
You can use any two of the points to find the slope of the line.
You will calculate that the slope is negative-3 . . . which you
might have realized as you read the story, looked at the numbers,
and saw that they are <u>firing 3 employees per month</u>.
("Losing" them doesn't quite capture the true spirit of what is happening.)
So your function ... call it ' W(n) ' . . . Workforce after 'n' months . . .
is <em>W(n) = 65 - 3n</em> .
Answer:
The sample size required is 865.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean is:
The margin of error of this interval is:
It is provided that all values of breakdown voltage are between 40 and 70.
So, the minimum value of breakdown voltage is, Min. = 40 and the maximum value of breakdown voltage is, Max. = 70.
Assume that the population standard of the distribution of breakdown voltage is known.
The standard deviation is:
The margin of error is, MOE = 1 kV.
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
Thus, the sample size required is 865.