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Bad White [126]
3 years ago
13

Gena wants to estimate the quotient of –21.87 divided by 4.79. Which expression shows the best expression to estimate the quotie

nt using front-end estimation?
Mathematics
2 answers:
Jobisdone [24]3 years ago
6 0
You haven't shared the list of expressions from which you are to choose an answer.

However:  you can perform this estimation yourself as follows:

Round off both -21.87 and 4.79.  -21.87 goes to -22 and 4.79 to 5.  Then
a good estimate of -21.87 divided by 4.79 would be -22/5, or -4.4.
loris [4]3 years ago
3 0

Answer:

\frac{-22}{5}=-4.4

Step-by-step explanation:

A good estimation always starts from the nearest whole numbers. This is a front-end for we maintain one number, -22 for the -21.87 and 5 and we place zeros to the right of it.

-21.87\approx-22\\4.79\approx 5

Since -21.87 is closer to -22.00, and 4.79 is closer to 5.00

Then

\\\frac{-21.87}{4.79}=-4.56 \\\frac{-22}{5}=-4.4

So, We can see that from 0.16 our estimative was quite close.

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You go to the store and grab a candy bar that costs $2. However, when you get to the cashier, you see that you are being charged
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5. From 13 friends to 14 friends
LUCKY_DIMON [66]

Answer:

That would be 1

Step-by-step explanation:

To get 13 out of 14 you must add 1.

7 0
2 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
An ice-skating competition lasted three days. Day one had an attendance of 16,390 people. Day two had an attendance of 16,550 pe
lana [24]

Answer:

Day\ 3 = 16237

Day\ 1 = 16390

Day\ 2 = 16550

Step-by-step explanation:

Given

Day\ 1 = 16390

Day\ 2 = 16550

Day\ 3 = 16237

Required

Order from least to greatest

Comparing 16390, 16550 and 16237.

The order of arrangement from least to greatest is:

16327, 16390 and 16550.

So, we have:

Day\ 3 = 16237

Day\ 1 = 16390

Day\ 2 = 16550

6 0
3 years ago
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