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-Dominant- [34]
3 years ago
15

5. Simplify the expression -3 1/6 dividend by -1 4/9

Mathematics
2 answers:
eimsori [14]3 years ago
7 0

Answer:

57/26 or 2 5/26

Step-by-step explanation:

iVinArrow [24]3 years ago
4 0
I think it’s 57/26 I hope I helped you
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5÷5+6÷6÷6÷6÷6÷6÷6÷6÷6÷6×6×7+7+8+9+3+5*6*6
Reil [10]

Answer:

208.00015

Step-by-step explanation:

Use a calculator. I'm sorry, there's no other way

4 0
3 years ago
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Which algebraic expression represents “the quotient of 7 and number”?
Drupady [299]
The correct option would be
A)7/n

As quotient deals with the division
I hope that helped!
6 0
3 years ago
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Subtraction of integers
Nataliya [291]

Answer:

First, keep the first number, Second, change the operation from subtraction to addition, Next, get the opposite sign of the second number (known as the subtrahend) and Lastly, proceed with the regular addition of integers.

Step-by-step explanation:

3 0
3 years ago
9) Gabe has a 40¢-off coupon for any kind of popcorn. He can choose
Vadim26 [7]

Answer:

Per ounce better buy is <em>Happy popcorn</em>.

Step-by-step explanation:

Given that:

Happy popcorn price for 16 ounces = $1.39

Popper popcorn price for 34 ounces = $2.79

Discount coupon present with Gabe = 40 ¢ = $0.40

To find:

Which brand is the better buy per ounce?

Solution:

First of all, let us calculate the price that Gabe has to pay after the discount coupon being applied.

Price for 16 ounces of Happy popcorn after discount = $1.29 - $0.40 = $0.99

Price for 1 ounce of Happy popcorn after discount = \frac{\$0.99}{16} = $0.062

Price for 34 ounces of Popper popcorn after discount = $2.79 - $0.40 = $2.39

Price for 1 ounce of Popper popcorn after discount = \frac{\$2.39}{34} = $0.070

Clearly, per ounce price of Happy popcorn is lesser than that of Popper popcorn.

Therefore per ounce better buy is <em>Happy popcorn</em>.

6 0
2 years ago
Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred
Ksivusya [100]

1. m\angle BAC=m\angle CAD,\ m\angle ACB=m\angle ADC=90^{\circ}, then m\angle ABC=m\angle ACD and triangles ADC and ACB are similar by AAA theorem.


2. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{AC}{AB}= \dfrac{AD}{AC}.


3. Knowing lengths you could state that \dfrac{b}{c}= \dfrac{e}{b}.


4. This ratio is equivalent to b^2=ce.


5. m\angle ABC=m\angle CBD,\ m\angle ACB=m\angle CDB=90^{\circ}, then m\angle BAC=m\angle BCD and triangles BDC and BCA are similar by AAA theorem.


6. The ratio of the corresponding sides of similar triangles is constant, so


\dfrac{BC}{BD}= \dfrac{AB}{BC}.


7. Knowing lengths you could state that \dfrac{a}{d}= \dfrac{c}{a}.


8. This ratio is equivalent to a^2=cd.


9. Now add results of parts 4 and 8:


b^2+a^2=ce+cd.


10. c is common factor, then:


b^2+a^2=c(e+d).


11. Since e+d=c you have a^2+b^2=c\cdot c=c^2.



7 0
3 years ago
Read 2 more answers
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