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3 years ago

a rectangular solid has a base with length 2cm and width 8 cm if the volume of the solid is 160cm^3 find the ht

Mathematics

1 answer:

wlad13 [49]3 years ago

5 0

Let the height be h.
2 x 8 x h = 160
h = 10
therefore the height is 10cm

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<img src="https://tex.z-dn.net/?f=14r%20-%208r%3D%20126" id="TexFormula1" title="14r - 8r= 126" alt="14r - 8r= 126" align="absmi

LuckyWell [14K]

14r – 8r=126

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3 years ago

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3 years ago

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A class has 12 males and 15 females. There's 7 males and 9 females in class who plays tennis. If a student is chosen from the cl

Vsevolod [243]

First, let's make a two-way table using a matrix:

$\left[\begin{array}{cccc}&Tennis&No&Total\\Male&7&5&12\\Female&9&6&15\\Total&16&11&27\end{array}\right]$

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3 years ago

Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

<u>Answer:</u> The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

<u>Step-by-step explanation:</u>

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

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3 years ago

Devonte used the change of base formula to approximate log4(x+2)?

ArbitrLikvidat [17]

The formula is logb x = logd x / logd b

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ITs A

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3 years ago