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attashe74 [19]
3 years ago
10

The fox population in a certain region has an annual growth rate of 6% per year. In the year 2012, there were 24,900 foxes count

ed in the area. What is the fox population predicted to be in the year 2020? (Round your answer to the nearest whole number.)
Mathematics
1 answer:
earnstyle [38]3 years ago
7 0
<h3>Answer:</h3>

39,687

<h3>Explanation:</h3>

Each year, the population is multiplied by (1 +6%) = 1.06. After 8 years, it will have been multiplied by that value 8 times, so is 1.06^8 times the starting value.

... 24,900 × 1.06^8 ≈ 39,687

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A scale model of a building is 6in tall. The scale of the model is 1in. :50ft. How tall is the actual building?​
saw5 [17]

Answer:

300 ft

Step-by-step explanation:

3 0
3 years ago
An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t
ratelena [41]

Answer with Step-by-step explanation:

We are given that height of projectile after t seconds is given by

h(t)=96t-16t^2

a.h(t)=144 ft

144=96t-16t^2

16t^2-96t+144=0

t^2-6t+9=0

t^2-3t-3t+9=0

t(t-3)-3(t-3)=0

(t-3)(t-3)=0

t-3=0

t=3

After 3 s, the height of the project will be 144 feet in the air.

b.h(t)=0

96t-16t^2=0

16t(6-t)=0

16t=0\implies t=0

6-t=0\implies t=6

At t=0, the initial position of projectile

At t=6 s , the projectile will hit the ground.

6 0
3 years ago
A projectile is fired at such an angle that the vertical
svetoff [14.1K]

(a) The projectile remains in the air for 10 seconds

(b) It travels a horizontal distance of 600 meters

Step-by-step explanation:

A projectile is fired at such an angle that

1. The vertical  component of its velocity is 49 m/sec

2. The horizontal  component of its velocity is 60 m/sec

We need to find:

(a) How long the projectile remains in the air

(b) The horizontal distance it travels

∵ The vertical distance y = u_{y} t - \frac{1}{2} g t², where

u_{y} is the vertical  component of its velocity, g is the acceleration

of gravity and t is the time

∵ y = 0 ⇒ it return to the same initial height

∵ u_{y} = 49 m/s

∵ g = 9.8 m/s²

- Substitute these values in the rule above

∴ 0 = 49 t - \frac{1}{2} (9.8) t²

∴ 0 = 49 t - 4.9 t²

- Take t as a common factor

∴ 0 = t (49 - 4.9 t)

- Equate each term by 0

∴ t = 0 ⇒ at initial position

∴ 49 - 4.9 t = 0

- Add 4.9 t to both side

∴ 49 = 4.9 t

- Divide both sides by 4.9

∴ t = 10 seconds

(a) The projectile remains in the air for 10 seconds

∵ The horizontal distance = u_{x} t, where u_{x} is the

   horizontal component of its velocity

∵ u_{x} = 60 m/sec

∵ t = 10 seconds

∴ x = 60 × 10 = 600 meters

(b) It travels a horizontal distance of 600 meters

Learn more:

You can learn more about the component of velocity in brainly.com/question/4464845

#LearnwithBrainly

3 0
3 years ago
−5x+2y=9<br> y=7x<br> ​x=<br> y=
Serhud [2]

- 5x+2y=9 \\ y=7x

We know that y=7x, so we just need tu put it into the 1st equation

- 5x + 2 \times 7x = 9 \\  - 5x + 14x = 9 \\ 9x = 9 | \div 9 \\ 9x \div 9 = 9 \div 9 \\ x = 1

So we found x. Now we can find y

y = 7 \times 1 \\ y = 7

Answer:

x=1, y=7; or (1;7)

4 0
3 years ago
Find the value of x that makes A || B.<br> x=?
Norma-Jean [14]

Answer:

78

Step-by-step explanation:

a

7 0
3 years ago
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