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Alisiya [41]
3 years ago
9

Need this answered quick

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

95.7942857 pie form hope this is right got it off the internet so yeah



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Which decimal is equivalent to 17/20 ?
ohaa [14]
0.85 is the decimal equivalent of 17/20.
4 0
3 years ago
5÷root3+root2 mark brainliest
Nikolay [14]

Answer:

It’s 123456

Step-by-step explanation:

23456

6789

980

3 0
3 years ago
What is the nearest thousand place for 3,429
muminat
If the place to the right of where you are rounding is 5 or higher, you have to round up. If it is 4 or lower, you have to round down. In the hundreds place, there is a 4. That's lower than 5 meaning that you round down/stay. So, the nearest thousands place is 3,000.
8 0
4 years ago
For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0
3 years ago
Solve for n.<br> 2n+3=-3.2
Vladimir [108]

Answer:

n= -3.1

Hope this helps!

4 0
3 years ago
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