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alexgriva [62]
3 years ago
14

Solve for x. -3x = -9

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

3

Step-by-step explanation:

divide both sides by -3

-9/-3=3

Llana [10]3 years ago
4 0

Answer:

x = 3   i hope this helps!   :)

Step-by-step explanation:

given   -3x = -9

flip the negative signs to positive signs   3x = 9

divide both sides by 3   x = 3

answer   x = 3

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Equation -1-7v+3= how do i slove this i dont know
TEA [102]
Negative one minus negative seven times volume plus three equals BLANK. If v is a variable, the question is wrong.
7 0
3 years ago
What is equivalent to<br>x2+ 14x = -13​
postnew [5]

Answer:

X= 1 AND 13

Step-by-step explanation:

x2+14x = -13

by completing the square method

you add the square of half the coefficient of b to both sides

which is (14/2)^2

x^2+14x+(7^2) = -13 +(7^2)

x^2 + 7^2 = -13 + 49

x^2 + 7^2 = 36

(x + 7)^2 = 36

find the square root of both sides

(x+7) = + or - 6

x=7-6 ; 1

or

x= 7+6 ; 13

8 0
3 years ago
(50 POINTS!!!) find the total surface area and volume, then multiply by $0.004. please show your work!!
mrs_skeptik [129]

The Total surface area of the square pyramid = 115.2 in.²

The Volume of the square pyramid = 1,024 in.³.

<h3>What is the Total Surface Area of a Square Pyramid?</h3>

The total surface are of a square pyramid is given as: TSA = SA = 1/2(P × l), where:

P = perimeter of the square base

l = slant height of the pyramid

<h3>What is the Volume of a Square Pyramid?</h3>

The volume of a square pyramid = 1/3(a³ × h), where:

a = edge of the square base

h = height of the pyramid

Find the Total surface area of the Pyramid:

P = 4(a) = 4(8) = 32 in.

l = 7.2 in.

Total surface area of the square pyramid = 1/2(32 × 7.2)

Total surface area of the square pyramid = 115.2 in.²

Volume of the square pyramid:

a = 8 in.

h = 6 in.

Volume of the square pyramid = 1/3(8³ × 6)

Volume of the square pyramid = 1,024 in.³

Learn more about the square pyramid on:

brainly.com/question/3688277

#SPJ1

6 0
2 years ago
12. Find the area lying above the x - axis and below the parabolic curve y = 4x - x2.
Margarita [4]
First we find the zeroes so we don't take the integral of negative bits

4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4

\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)=  10.6666666666 or aout 10 and 2/3

C is answer
6 0
3 years ago
Help me on number problem 4 please.
Tresset [83]
The answer is 460 because you have to subtract
3 0
3 years ago
Read 2 more answers
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