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xeze [42]
3 years ago
14

Let f(x) = -6x + 3 and g(x) = 5x + 4. Find fg and state its domain.

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

f(g(x))=-30x-21

The domain is all real numbers

Step-by-step explanation:

we have

f(x)=-6x+3

g(x)=5x+4

we know that

(fog)(x)=f(g(x))

In the function f(x) substitute the variable x by the function g(x)

so

f(g(x))=-6(5x+4)+3

f(g(x))=-30x-24+3

f(g(x))=-30x-21

This is a linear function (equation of a line)

The domain is all real numbers

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In a hospital wing there are 12 doctors. There are 20 more nurses than doctors. What proportion of the staff are nurses? Write y
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Answer:

8/11

Step-by-step explanation:

There are 12 + 20 = 32 nurses and 32 + 12 = 44 staff in all. The answer is 32 / 44 = 8 / 11.

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I need help with this question for algebra 1 please ( worth 100 points)
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Step-by-step explanation:

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3 years ago
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If a toy rocket is launched vertically upward from ground level with an initial velocity of 120 feet per second, then its height
german

Answer:

Time = 7.5\ seconds

Step-by-step explanation:

Given

Equation:\ h(t) = -16t^2 + 120t

Initial\ Velocity = 160ft/s

Required:

Determine the time taken to return to the ground

From the equation given; height (h) is a function of time (t)

When the rocket returns to the ground level, h(t) = 0

Substitute 0 for h(t) in the given equation

h(t) = -16t^2 + 120t

becomes

0 = -16t^2 + 120t

Solve for t in the above equation

-16t^2 + 120t = 0

Factorize the above expression

-4t(4t - 30) = 0

Split the expression to 2

-4t = 0\ or\ 4t - 30 = 0

Solving the first expression

-4t = 0

Divide both sides by -4

\frac{-4t}{-4} = \frac{0}{-4}

t = \frac{0}{-4}

t =0

Solving the second expression

4t - 30 = 0

Add 30 to both sides

4t - 30+30 = 0+30

4t  = 30

Divide both sides by 4

\frac{4t}{4}  = \frac{30}{4}

t  = \frac{30}{4}

t = 7.5

Hence, the values of t are:

t =0 and t = 7.5

t =0 shows the time before the launching the rocket

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3 years ago
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3 years ago
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A bricklayers union charges monthly dues of $3 plus $.18 for each hour worked during
Radda [10]

Answer:

160 hours

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31.80=3+.18(hours)

28.8=.18(hours)

160=hours

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