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Andrej [43]
3 years ago
6

According to the Rational Root Theorem, the following are potential roots of f(x) = 60x2 – 57x – 18. -6/5, -1/4, 3, 6 Which is a

n actual root of f(x)?
Mathematics
2 answers:
lidiya [134]3 years ago
8 0

Answer:

B. -1/4

Step-by-step explanation:

got it right on quiz

taurus [48]3 years ago
7 0
As for Rational Root Theorem, we substitute the given choices in the equation and if the value of f(x) is equal to 0 then, the certain choice is a root of the equation.

(1)     -6/5 :    f(x) = 60(-6/5)^2 - 57(-6/5) - 18  = 136.8
(2)     -1/4:     f(x) = 60(-1/4)^2 - 57(-1/4) - 18 = 0
(3)         3:     f(x) = 60(3)^2 - 57(3) - 18 = 351
(4)         6:     f(x) = 60(6)^2 -57(6) - 18 = 1800

Thus, the answer is the second choice. 
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The probability that the sample of four balls contains two white balls and two red balls is 0.39.

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According to the given question.

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Now, the number of ways of selecting four marbles form an urn = ^{37} C_{4}

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As, we know that probability of an event is calculated by taking the ratio of total number of favorable outcomes to the total number of outcomes.

Therefore, the probability that the sample of four balls contains two white balls and two red balls is given by

P(E) = \frac{^{20}C_{2} \times ^{17}C_{2}   }{^{37}C_{4}  }

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\implies P(E) = \frac{\frac{20(19)(17)(16)}{2(2)} }{\frac{37(36)(35)(34)}{(4)(3)(2)} }

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