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stellarik [79]
2 years ago
12

2×2+5×a3×3-7×2+5×-y​

Mathematics
1 answer:
allochka39001 [22]2 years ago
8 0

Answer:

15a^3 -5y -10

Step-by-step explanation:

Use PEMDAS to simplify and combine like terms

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A homeowner has 20 feet of fencing material to enclose a rectangular area for his pets. the rectangular area is adjacent to a ho
VikaD [51]
5X10=50 sq ft area
Around the 3 sides= 5+10+5=20
7 0
3 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
Which one should I choose.
Mice21 [21]

Answer: 9

54 ÷ 2

27

3x = 27

x = 9

7 0
3 years ago
Please help ...........​
sammy [17]

Answer:

Angle B = 80°

see attachment......

7 0
3 years ago
In the circle below, AD is a diameter and AB is tangent at A. suppose mADC=228. Find the measures of mCAB and mCAD. Type your nu
Tju [1.3M]

Answer:

m∠CAB = 66°

m∠CAD = 24°

Step-by-step explanation:

<em>m∠CAB</em>

The given parameters are;

The measure of arc m\widehat{ADC} = 228°

The diameter of the given circle = \overline{AD}

The tangent to the circle = \underset{AB}{\leftrightarrow}

The measure of m∠CAB and m∠CAD = Required

By the tangent and chord circle theorem, we have;

m∠CAB = (1/2) × m\widehat{AC}

However, we have;

m\widehat{AC} + m\widehat{ADC} = 360° the sum of angles at the center of a circle is 360°

∴ m\widehat{AC} = 360° - m\widehat{ADC}

Which gives;

m\widehat{AC} = 360° - 228° = 132°

m\widehat{AC} = 132°

Therefore;

m∠CAB = (1/2) × 132° = 66°

m∠CAB = 66°

<em>m∠CAD</em>

Given that  \overline{AD} is the diameter of the given circle, we have

The tangent, \underset{AB}{\leftrightarrow}, is perpendicular to the radius of the circle, and therefore \underset{AB}{\leftrightarrow} is also perpendicular to the diameter of the circle

∴ m∠DAB = 90° which is the measure of the angle formed by two perpendicular lines

By angle addition property, we have;

m∠DAB = m∠CAB + m∠CAD

∴ m∠CAD =  m∠DAB - m∠CAB

By substitution, we have;

m∠CAD = 90° - 66° = 24°

m∠CAD = 24°

7 0
3 years ago
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